If
=3\sqrt{4-2x}+1)
and
=\sqrt{x}+4)
Both on their maximal domains. How would I find range of
))
?
This is from a paper 1.
I guess you can do it by saying that the minimum will occur when

is a minimum and that expression is minimum when

is minimum. This has a minimum of 0, so the minimum value must be

And for maximum, as x->-inf 4-2x->inf so g(f(x))->inf.
So we conclude the range is [5, inf).
BUT, this is a 2 mark question, do they really expect this much thinking in a 2 mark question? There has to be a simpler way...
Also, is the above reasoning valid?
In the solutions, they give no reasoning

They just sketch it and say the range. Secondary part of this question is: How would I sketch the graph of g(f(x)) without a calculator?