VCE Methods Question Thread!

[Max Kawasakii]

I am probably posting in the wrong thread, so feel free to delete or move the comment, but I was wondering if anyone has solutions to the MAV 2016 Exam 2 and TSSM 2016 exam 2, that they might be able to share on a drive or email? Thanks in advance

[zhen]

This might seem obvious, but how do I find the derivative in question 4a in the 2015 VCAA exam 1?
Also, how would I know the shape of the graph for 4b?
Thank you!

Just take the derivative and remember to just put the factor back out the front. For 4b, you need to know the overall shape of a cubic. Also note that at the point (-2,0) it touches the x-axis and goes back down. So that’s a turning point.

[GloriousHeights]

Just take the derivative and remember to just put the factor back out the front. For 4b, you need to know the overall shape of a cubic. Also note that at the point (-2,0) it touches the x-axis and goes back down. So that’s a turning point.

That's what I got too, but VCAA has the solution [tex\]f'(x)=frac{3}{2}x(x+2)[/tex]
Have they just factorised it more?

[zhen]

That's what I got too, but VCAA has the solution [tex\]f'(x)=frac{3}{2}x(x+2)[/tex]
Have they just factorised it more?

They’ve just taken out the 3x, so basically yea they factorised more.

[rnrn]

How would I integrate this?

{ xln(x) dx

( { is meant to be the curvy intergration symbol thing)

[zhen]

How would I integrate this?

{ xln(x) dx

( { is meant to be the curvy intergration symbol thing)

The first thing that comes to mind is integration by parts, which isn’t in the syllabus. Next thing that comes to mind is to do an integration by recognition type thing. Note that

From this you could do integration by recognition.

[plsbegentle]

just adding to what zhen has said, since you cant integrate xln(x) properly, he found the derivative, which is done by using the product rule. Now all you have to do now is make it look like the original equation again and to do that you divide both sides by two and minus both sides by x. So, you end up with 1/2(dy/dx((x^2ln(x))-x)=xln(x). Now you can easily anti-differentiate, dy/dx cancels out and your left with x^2ln(x) and x^2/2( integrate the x). You can leave it as that or you can further simplify by dividing it all by 2. Hope that makes sense (bit messy).

[Rieko Ioane]

Are we allowed to write infinities in the terminals when finding the areas of continuous distributions?

I've been told it is mathematically correct to but apparently in VCE they want you to write it with a limit??

[Sine]

Are we allowed to write infinities in the terminals when finding the areas of continuous distributions?

I've been told it is mathematically correct to but apparently in VCE they want you to write it with a limit??

hmm it isn't really clear in the methods course since it hasn't really come up before but definitely use a limit. Subbing in infinity is just matheamtically dodgy.

[CarrymetoUni]

Can someone show me how to do Q3d from the 2012 VCAA Exam 2.

[Ahmad_A_1999]

http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2017/nht/2017MM2-nht-w.pdf

Could someone please help me with MC Question 8, I'm not sure how to go about finding the average value of a hybrid function 

[Syndicate]

http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2017/nht/2017MM2-nht-w.pdf

Could someone please help me with MC Question 8, I'm not sure how to go about finding the average value of a hybrid function 

Calculate the area by either considering this area as a square and a triangle or a trapezium and triangle.

Area = a^2 (The area of the triangles cancel out, as they are symmetric)
Average value = a^2/2a = a/2 (Using the formula \( \frac{1}{b-a} \int^{b}_{a} f(x) \space dx\) )

= Option D

[Ahmad_A_1999]

Calculate the area by either considering this area as a square and a triangle or a trapezium and triangle.

Area = a^2 (The area of the triangles cancel out, as they are symmetric)
Average value = a^2/2a = a/2 (Using the formula \( \frac{1}{b-a} \int^{b}_{a} f(x) \space dx\) )

= Option D

I still don't get it 
Could someone please also have a look at MC 11, I don't know anything

http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2017/nht/2017MM2-nht-w.pdf

[helpmepls112]

Hi guys,

Just wondering if question q2 e of 2014 exam 2 is still in the course?

probs is just a little unsure

thanks

[Rusten]

Hi guys,

Just wondering if question q2 e of 2014 exam 2 is still in the course?

probs is just a little unsure

thanks

It's related rates, so it's not explicitly stated in the course as it used to be. However, as I've seen other people say, you're best off knowing it juuuust in case as it's just an application of the chain rule. There's a good guide on the methods resources page I think. You never know what sus stuff vcaa will pull off.

EDIT: I thought you were talking about 2f... my bad. 2e is definitely still on the course (I think), it's just algebraic manipulation etc with the info they give you.