VCE Methods Question Thread!

[vceme]

things that i must look over today to ensure that i get a c+ on this exam?
- from someone who hasn't done any methods study for a very very long time. i just need a 25

[Freddie Hg]

things that i must look over today to ensure that i get a c+ on this exam?
- from someone who hasn't done any methods study for a very very long time. i just need a 25

chain rule quotient rule, brush up on sketching and basic probability, and statistical interference (guaranteed going to be there as it always has since 2016)

Good luck hope you you get the score you want 

[vceme]

chain rule quotient rule, brush up on sketching and basic probability, and statistical interference (guaranteed going to be there as it always has since 2016)

Good luck hope you you get the score you want 

thank you!!!! what a legend.
if anyone has other ideas, please send them my way 

[Bri MT]

thank you!!!! what a legend.
if anyone has other ideas, please send them my way 

The VCAA exam 1s tend to follow a pretty reliable pattern,  so go through a couple of exam 1s and make sure you can do the questions that most of the state gets right (the examiners report will tell you what percentage of people got marks for that question)

[fruitbowl34]

Can anyone help me do this question? Thanks!

[Unsplash]

Can anyone help me do this question? Thanks!

[fruitbowl34]

Are the northern hemisphere exams usually harder than the usual exams?? Because in exam 1 their graphs include cos/sin/tan. Does that mean there is a possibility for us to sketch a tan/cos/sin graph this year?

[snip]

Hey guys! Just a question about rounding. Hypothetically, say that a question was asking for the minimum amount of time it takes to cook a cake to the nearest minute. If it took at least 20.3 minutes to cook a cake, would you round that down to 20, even though a cake wouldn't be able to cook in 20 minutes, or up to 21, which isn't the nearest integer, but the smallest integer for which the question holds true?

Thanks so much!

[Unsplash]

Are the northern hemisphere exams usually harder than the usual exams?? Because in exam 1 their graphs include cos/sin/tan. Does that mean there is a possibility for us to sketch a tan/cos/sin graph this year?

If anything, on average I'd say combined (Exam 1 and 2), NHT exams are easier, but that's obviously a personal opinion.

Yes you could be asked to sketch a trig graph, it is on the study design, however hasn't appeared for a while on a normal timetable exam. Make sure you are comfortable sketching them with basic transformations such as translations, reflections and dilations.

[Azzzz]

Hey guys! Just a question about rounding. Hypothetically, say that a question was asking for the minimum amount of time it takes to cook a cake to the nearest minute. If it took at least 20.3 minutes to cook a cake, would you round that down to 20, even though a cake wouldn't be able to cook in 20 minutes, or up to 21, which isn't the nearest integer, but the smallest integer for which the question holds true?

Thanks so much!

Since it is the minimum amount of time to the nearest minute I would round up to 21 because if you round down to 20 that means there's still an extra 0.3 minutes it takes to make the cake completely

[Freddie Hg]

How would you explain question 4 fi with limits for 2016 exam 2 mm?

[EllingtonFeint]

Hello.
Cos of my bio exam, I’ve missed out on a bunch of 1/2 Methods classes so I was wondering if somebody could please explain to me how to work out the following problem please?

Thank you

[Azzzz]

Hello.
Cos of my bio exam, I’ve missed out on a bunch of 1/2 Methods classes so I was wondering if somebody could please explain to me how to work out the following problem please?

Thank you

In order to find maximum and minimum points, you must first derive the function. The derivative will give you the gradient at any x point.
So f'(t)= 42-10t
Once you derive the function make it equal to zero, as maximum and minimum points are also known as stationary points which have a gradient of 0
f'(t)=0
-42=-10t
t=42/10
 =21/5 or 4.2
So that t value is when the function has a maximum thus the time it takes to reach its maximum height is 4.2 seconds.
Then in order to find its maximum height substitute the t value into the original function.
f(4.2)=42(4.2)-5(4.2)^2
=88.2 metres
Hope this helped

[EllingtonFeint]

In order to find maximum and minimum points, you must first derive the function. The derivative will give you the gradient at any x point.
So f'(t)= 42-10t
Once you derive the function make it equal to zero, as maximum and minimum points are also known as stationary points which have a gradient of 0
f'(t)=0
-42=-10t
t=42/10
 =21/5 or 4.2
So that t value is when the function has a maximum thus the time it takes to reach its maximum height is 4.2 seconds.
Then in order to find its maximum height substitute the t value into the original function.
f(4.2)=42(4.2)-5(4.2)^2
=88.2 metres
Hope this helped

Thank you!

[fun_jirachi]

Hello.
Cos of my bio exam, I’ve missed out on a bunch of 1/2 Methods classes so I was wondering if somebody could please explain to me how to work out the following problem please?

Thank you

In order to find maximum and minimum points, you must first derive the function. The derivative will give you the gradient at any x point.
So f'(t)= 42-10t
Once you derive the function make it equal to zero, as maximum and minimum points are also known as stationary points which have a gradient of 0
f'(t)=0
-42=-10t
t=42/10
 =21/5 or 4.2
So that t value is when the function has a maximum thus the time it takes to reach its maximum height is 4.2 seconds.
Then in order to find its maximum height substitute the t value into the original function.
f(4.2)=42(4.2)-5(4.2)^2
=88.2 metres
Hope this helped

Just to add on to this, note that in an exam situation you would have to prove that the stationary point is a maximum by either using a sign table to determine the nature of the curve prior to and after to stationary point, or use the second derivative to determine the concavity at that point (which also tells you the nature of the curve). For this exercise it seems unnecessary since it doesn't ask you, and it infers that there is a maximum and by deriving there is only one stationary point, but it's just a good thing to keep in mind in the future.