VCE Methods Question Thread!

[integrationbyrecognition]

For the second question: The issue is that I don't think you can get the solution using the discriminate. Correct me if I'm wrong.

There are probably other ways to do the question but surely the discriminant would also work?

[integrationbyrecognition]

yeah it's possible to get 1 mark if you did everything else right, but depends on the assesor.

Having said that, most assesors don't like give 0 marks for questions worth (2,3 etc marks) so if you have written something that makes sense you should get at least 1 mark.

Did you think this exam was harder than usual sine?

[tinkerbell101]

would it be possible to get a study score betwene low and mid 40's?

sacs top 10% (strong cohort)
exam 1: a+ (37/40)
exam 2: a+ (65-70/80

thanks

[integrationbyrecognition]

would it be possible to get a study score betwene low and mid 40's?

sacs top 10% (strong cohort)
exam 1: a+ (37/40)
exam 2: a+ (65-70/80

thanks

Considering the difficulty of today's exam and assuming tomorrow's exam is hard as well, I would say it's possible

[vceme]

hey everyone,
i hope you all went well with your methods exam today.
following my last exam 1 post, anyone have any advice on what to look over for exam 2 
(#justneeditfortheprereq)

[Sine]

hey everyone,
i hope you all went well with your methods exam today.
following my last exam 1 post, anyone have any advice on what to look over for exam 2 
(#justneeditfortheprereq)

look over concepts any that weren't covered in exam 1 - often they will try to test every concept at least once across both exams.

If you have looked over the answers of exam 1 I would be taking note of the type of mistakes you make under pressure and make sure you don't make those same type of mistakes on exam 2.

[S_R_K]

I would be surprised if stating that the discriminant = 0 would get you a mark for 8(b), for two reasons:

One: It's an extremely generic response. The discriminant of what quadratic?

Two: When you do find a quadratic factor and set it equal to 0, you'll find that the discriminant of this quadratic is always positive, hence discriminant = 0 has no solution for k. What you needed to notice in this question is that, for some value of k, the coefficient of x^2 is 0, and this is how you'll get one point of intersection. (For any other value of k, the discriminant is positive, hence there are two points of intersection).

[minhalgill]

ok so , for the last question in the methods exam, part (a) and (b), i subbed in a value for n, rather than have the answer in terms of n? am i likely to get any marks for that?

[integrationbyrecognition]

ok so , for the last question in the methods exam, part (a) and (b), i subbed in a value for n, rather than have the answer in terms of n? am i likely to get any marks for that?

I did the same, can someone please tell us if we're likely to get any marks?

[S_R_K]

It was a 2 mark question, so you might get partial marks if you showed some correct working. The problem is that you're given the antiderivative in the question, so you probably won't get any working marks for antidifferentiating x*sin(x).

You probably will have needed to show the step where you substitute n*pi and (n+1)*pi into the antiderivative, in order to get at least 1 mark.

[integrationbyrecognition]

It was a 2 mark question, so you might get partial marks if you showed some correct working. The problem is that you're given the antiderivative in the question, so you probably won't get any working marks for antidifferentiating x*sin(x).

You probably will have needed to show the step where you substitute n*pi and (n+1)*pi into the antiderivative, in order to get at least 1 mark.
Do you remember if it was the odd or even one that was two marks?
For the odd I subbed in x = 1 for n and for the even I subbed in x = 0 for n and for both questions I evaluated the antiderivative with the terminals substituted in, so my answer is obviously wrong, but since I still used the correct method of evaluating a definite integral, is there still a chance of 1/2?

[integrationbyrecognition]

Do you remember if it was the odd or even one that was two marks?
For the odd I subbed in x = 1 for n and for the even I subbed in x = 0 for n and for both questions I evaluated the antiderivative with the terminals substituted in, so my answer is obviously wrong, but since I still used the correct method of evaluating a definite integral, is there still a chance of 1/2?

[S_R_K]

Do you remember if it was the odd or even one that was two marks?
For the odd I subbed in x = 1 for n and for the even I subbed in x = 0 for n and for both questions I evaluated the antiderivative with the terminals substituted in, so my answer is obviously wrong, but since I still used the correct method of evaluating a definite integral, is there still a chance of 1/2?

It depends on how generous the assessors are. But I suspect not. It's a pretty fundamental error to substitute in a particular value of n.

[minhalgill]

for question 2 part (a), i didnt take 2 common when antidifferentiating, and ended up getting c=-1+loge(2)/2? is that wrong?

[passbleh24]

How would I find the average value over the interval -a to a ?