8.a)
To calculate the initial speed of the golf ball as it leaves the ground:
v
2 = u
2 + 2as
0 = u
2 + 2 x - 9.8 x 1.5
u = (29.4)
1/2 = 5.42 m/s
b)
For both objects - to calculate the speed they hit the ground:
v
2 = u
2 + 2as
v
2 = 0 + 2 x 9.8 x 2
v = (39.2)
1/2 = 6.26 m/s
Change in v for golf ball:
= v
final - v
initial= -5.42 - 6.26 = -11.68 = 11.68 m/s in opposite direction to initial (I'm not sure about those units

)
Change in v for tomato:
= v
final - v
intial= 0 - 6.26 = -6.26 = 6.26 m/s in the opposite direction to initial (I'm not sure about those units

)
Therefore, the golf ball has a greater change in velocity
9. a)
v
2 = u
2 + 2as
0 = 8 + 2 x -2 x s
-8 = -4s
s = 2m
b)
v = u + at
0 = 8 +-2t
-8 = -2t
t = 4s
c)
Give that 4 seconds have already elapsed (calculated in b) we need to find her velocity after 1 second of falling down the ramp:
v = u + at
v = 0 + 2 x 1
v = 2m/s
In the above equations; a = acceleration, u = initial velocity, v = final velocity, s = distance traveled, s = time taken/elapsed
As of yet, I haven't read over this work to ensure all answers are correct, I'll do that now.