Homework questions thread

[charmanderp]

You don't have to know about the tertiary structure of DNA.

[spongebob-7]

oh really, thanks good as lol, cos haven't i done much revision, what would you say are the most important parts of DNA and sugars that you would have to know

[pi]

You don't have to know about the tertiary structure of DNA.

What spongebob-7 referred to is the secondary structure though

[charmanderp]

Indeed, I was just pointing out a useless fact I think Choong might have read the question incorrectly though because hydrogen bonding between Z groups occurs in the tertiary structure of polypeptides rather than DNA.

[Truck]

The tertiary structure of DNA is actually when DNA bonds with histones to form a histone group, and it's a form of ionic bonding.

[ggxoxo]

Am I missing something but does 1-butanol have 4 chem environment (because I keep getting 5)

[charmanderp]

4 carbon environments, 5 hydrogen environments.

[ggxoxo]

4 carbon environments, 5 hydrogen environments.

I thought so... Lisachem 2008 said 4 H environments though so I guess they're wrong...

[sahil26]

Can some please explain what Bagasse is?

[nina_rox]

Does anyone know what is the test for amide bond is? Any help is appreciated

[afeichuu]

Can someone please help me with this question, it's from lisachem learning materials review questions

6.5L of oxygen is required to completely convert 1.0L of gaseous hydrocarbon fuel to carbon dioxide and water. If the volumes were measured at the same temperature and pressure the hydrocarbon would be:
A. CH4
B. C2H6
C. C4H10
D. C6H6

the answer is C

thanks

[Somye]

Okay, so first of all, remember the gas equation; pv = nrt. Now in this case, t,p,r are all constants, so in other words v is preportional to n. therefore, you need 6.5 mol of Oxygen to completely combust this hydrocarbon

So you have
2 C(x)H(y) + 13O2 ---------> (2x)CO2 + (y)H20

If you equate the coefficents, 4x + y = 26, and you can see that C is the answer