Help!

[Stick]

I'm stuck on this question:

A biathlon event involves running and cycling. Kim can cycle 30km/h faster than she can run. If Kim spends 48 minutes running and a third as much time again cycling in an event that covers 60km, how fast can she run?

Thanks for your help!

[b^3]

1) .....[1]



Now remember that
So sub into [1]


.....[1a]
Now
Sub into [1a]






Just remember its all about manipulating the speed equation and finding a couple of formulas

EDIT: FIXED IT

[sam_i_am]

to solve your problem you have to put it in an equation which is 60= 48/60 *x + 16/60 * (x+30) then you times it by 60 to get rid of the fraction,which makes it 3600=48*x+16*(x+30) then expand bracket, 3600 = 48*x+16*x+480 put like terms together, 3600= 64*x+480 takeaway 480, 3120= 64*x divide 64 which is 48.75 =x

[Stick]

Both are wrong. Sorry.

[b^3]

I'm stuck on this question:

A biathlon event involves running and cycling. Kim can cycle 30km/h faster than she can run. If Kim spends 48 minutes running and a third as much time again cycling in an event that covers 60km, how fast can she run?

Thanks for your help!

Ok I've fixed it in the post above, as the ratio between the time taken to cycle to the time taken to run should have been instead of as it is "a third as much time again"

Also note that the other method which sam_i_am outlined is quicker and more efficient when the right values are put in.

[Stick]

Thank you!