Question about motion

[Phy124]

V40 kΩ = I total × 40 kΩ = 0.205 × 40 = 8.2 V

I'm probably missing an obvious concept here (as displayed in my previous posts in this thread ) but I don't understand why 40kΩ is not being converted to 40,000Ω. Could anyone tell me why it's just left as 40kΩ?

Is the current in milliamps?

This would cause the 10³ and 10^-3 to cancel out.

i.e. 0.205 x 10^-3 x 40 x 10³ is the same as 0.205 x 40, if they were converted to Amps and Ohms respectively.

[Lasercookie]

I'm assuming you meant (bit confused with what I assumed to be subscripts):


Assuming that the working out here is correct, my suspicion would be with the units of current being used here. It's possible that it's for I, which would give the answer of 8.2 V:



But yeah, always work in SI Units, if what I guessed above is correct, then poor move by whoever wrote those solutions.

edit: damn, posted too slow, got beaten to it by a pony. 

[Genericname2365]

Thanks, that clears it up.