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November 01, 2025, 08:02:22 pm

Author Topic: Double angle and half angle formulae help!  (Read 869 times)  Share 

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dianzhang

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Double angle and half angle formulae help!
« on: March 07, 2012, 05:47:54 pm »
0
i dont get what to do
same with cos(2x)cos(pie/3) + sin(2x)sin(pie/3) = [sprt(3)]/2
and another question,
if sin(theta) = -3/7 and pie<theta<3pie/2 find sin(theta/2)
and another question,
simplify cos(4x)sin(4x)
i am so lost.

TrueTears

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Re: Double angle and half angle formulae help!
« Reply #1 on: March 07, 2012, 05:52:12 pm »
+1
4tanx = 6(2tanx/(1-tan^2x))

let u = tanx

4u = 6(2u/(1-u^2)

u = 0

solve tanx = 0
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dianzhang

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Re: Double angle and half angle formulae help!
« Reply #2 on: March 07, 2012, 06:02:26 pm »
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4tanx = 6(2tanx/(1-tan^2x))

let u = tanx

4u = 6(2u/(1-u^2)

u = 0

solve tanx = 0
how did you get to u=0

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Re: Double angle and half angle formulae help!
« Reply #3 on: March 07, 2012, 11:05:26 pm »
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4u = 8u / (1 - u^2)
4u(1 - u^2) = 8u
4u - 4u^3 - 8u = 0
-4u^3 - 4u = 0
u^3 + u = 0
u(u^2 + 1) = 0
u = 0 or u^2 = -1 --- NOT REAL
u = 0 is only real solution.
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