Login

Welcome, Guest. Please login or register.

November 01, 2025, 01:00:04 pm

Author Topic: Mr Study's 3/4 Questions  (Read 7118 times)  Share 

0 Members and 1 Guest are viewing this topic.

Mr. Study

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 494
  • Onion Knight
  • Respect: +18
Re: Mr Study's 3/4 Questions
« Reply #30 on: March 14, 2012, 04:55:30 pm »
0
How would I do this question?

A 15.00 g sample of an unstable hydrated salt, Na2SO4.xH2O was found to contain 7.05 g of water. The value of x in this formula is?

Thanks. :)
ᕕ( ᐛ )ᕗ

oliverk94

  • Guest
Re: Mr Study's 3/4 Questions
« Reply #31 on: March 14, 2012, 05:27:15 pm »
+1
m of Na2SO4 = 15 - 7.05 = 7.95 g

n(Na2SO4):n(xH2O)

7.95/142 g mol: 7.05/18 g mol

0.05598: 0.391667

Divide by smallest value

0.05598/0.05598: 0.391667/0.05598

1: 7

So the equation will be:
Na2SO4:7H2O

x=7

Mr. Study

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 494
  • Onion Knight
  • Respect: +18
Re: Mr Study's 3/4 Questions
« Reply #32 on: March 14, 2012, 05:36:17 pm »
0
Thank you for that! :)
ᕕ( ᐛ )ᕗ