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November 08, 2025, 08:18:08 am
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Author Topic: double absoute functon  (Read 723 times)  Share 

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henry14

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double absoute functon
« on: March 26, 2012, 07:02:12 pm »
0
l2+xl-1 =< 3-l2x+3l

- find the domain.


I'm stuck with this questio. :/
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Peanuts11

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Re: double absoute functon
« Reply #1 on: March 26, 2012, 07:14:16 pm »
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Quote from: henry14 on March 26, 2012, 07:02:12 pm
l2+xl-1 =< 3-l2x+3l

- find the domain.


I'm stuck with this questio. :/

Sketch both functions and look at the graph to solve.You'll have to find a of intersection, look at the graph where to use
(2+x) or -(2+x) and (2x-3) or -(2x-3)

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henry14

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Re: double absoute functon
« Reply #2 on: March 26, 2012, 07:25:07 pm »
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how do you find it algebraically?
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TrueTears

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Re: double absoute functon
« Reply #3 on: March 26, 2012, 07:29:57 pm »
+1
expand the modulus into a hybrid, splitting it into cases
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PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

#1procrastinator

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Re: double absoute functon
« Reply #4 on: March 29, 2012, 04:58:24 am »
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i'm interested in this too...bloody absolute values, still can't get my head around it >.>
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fred42

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Re: double absoute functon
« Reply #5 on: March 29, 2012, 12:22:35 pm »
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See attached.

I doubt this would ever be in a non-calculator exam.
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