Hallo.
I wanting to ask the following:
~from chem dimensions worksheet.
"A 2.890 g sample of steel was analysed for its manganese content in the following manner.
The sample was dissolved in concentrated nitric acid, producing manganese(II) ions.
Potassium persulfate, K2S2O8, was added to remove the carbon in the steel. This oxidised the carbon to carbon dioxide.
The virtually colourless manganese(II) ions were converted to deep purple permanganate (MnO4–) ions by boiling with a solution containing periodate (IO4–) ions. In this reaction the periodate ions are converted to IO3– ions.
Phosphoric acid was added in order to convert the yellow iron(III) ions to a colourless complex (so the iron ions would not interfere with the colorimetric MnO4– ion analysis).
The solution was diluted with distilled water to 1.00 L in a volumetric flask.
A series of standards was prepared, containing MnO4– ranging from 1.00 to 8.00 ppm.
The colorimeter was set to measure absorbance at 520 nm, and calibrated using a solvent blank. The absorbances of the standard solutions and the steel sample were taken and are given in the table below.
table: bla bla bla"
questions:
7 ) As well as water, what else should be added to the standards and the solvent blank and why?
8 ) Why was 520 nm a more appropriate wavelength than 400 nm for this analysis?
9 ) During calibration, the absorbance was set to zero using a solvent blank. Would your calculated percentage of Mn (m/m) have been affected had this not been done? Explain.
thanking you, sincerely, may the curry be with you.