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October 21, 2025, 08:56:17 pm

Author Topic: Using derivatives to find point of inflexion  (Read 748 times)  Share 

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soccerboi

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Using derivatives to find point of inflexion
« on: May 12, 2012, 06:09:20 pm »
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How do you test to see if a point is a point of inflexion? I know that you test a point to the left of it and right of it.
Is it correct to say: A point of inflexion occurs (by testing points on either side) when the derivative doesn't change signs an the second derivative changes sign?
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DisaFear

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Re: Using derivatives to find point of inflexion
« Reply #1 on: May 12, 2012, 06:15:29 pm »
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Indeed. If you look at the graph below, the gradient has the same sign on either side. The concavity changes, though, on either side, which the second derivative can tell you all about.

If f''(x)>0 over an interval, then the function f' is increasing over that interval, so the graph of f is concave up over that interval
And vice versa.




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Mao

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Re: Using derivatives to find point of inflexion
« Reply #2 on: May 15, 2012, 12:50:49 am »
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, , and

Alternatively, show that and first becomes non-zero for an odd
« Last Edit: May 15, 2012, 01:02:18 am by Mao »
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