Chemistry fundamentals- solubility product?

[Starlight]

Anyone know how to do this question? 


Calcium phosphate (Ca3(Po4)2) has a solubility product Ksp= 2.07 x 10^-33 at 25 degrees celsius. What is the concentrtion of Po43- ions in a saturated solution of Ca3(Po4)2?

(Answer is 1.1 x 10^-7 M)

[VivaTequila]

I do chemistry 1 and what is this?

[jinny1]

I do chemistry 1 and what is this?

lmao

Is swear some of the stuff we are learning is too freakking complicated ffs

[banditkeith]

We spent a lecture about that in Chem of Biomed so yeah.. lol
Is a concentration not specified for the saturated solution? There's probably some way to figure it out but I'm too tired to think...

[acrimony]

LOL The future is looking bright here

[thushan]

We spent a lecture about that in Chem of Biomed so yeah.. lol
Is a concentration not specified for the saturated solution? There's probably some way to figure it out but I'm too tired to think...

Can figure it out for a saturated solution; basically Qsp = Ksp in a saturated solution.

[VivaTequila]

I have a vague idea but no calculator

K= [Ca2+]^3 * [PO4 3-]^2 where n[Ca2+]= 2/3[PO4 3-]

thus K= ((2/3[PO4 3-] ))2 * [PO4 3-]^3

4/9 [PO4 3-]^5 = K.

9/4k = [PO4 3-]^5

5th Root of 9/4k = [PO4 3-]?

didn't work, no idea.

[thushan]

I have a vague idea but no calculator

K= [Ca2+]^3 * [PO4 3-]^2 where n[Ca2+]= 2/3[PO4 3-]

thus K= ((2/3[PO4 3-] ))2 * [PO4 3-]^3

4/9 [PO4 3-]^5 = K.

9/4k = [PO4 3-]^5

5th Root of 9/4k = [PO4 3-]?

didn't work, no idea.

n[Ca2+]= 3/2[PO4 3-] actually

[VivaTequila]

I have a vague idea but no calculator

K= [Ca2+]^3 * [PO4 3-]^2 where n[Ca2+]= 2/3[PO4 3-]

thus K= ((2/3[PO4 3-] ))2 * [PO4 3-]^3

4/9 [PO4 3-]^5 = K.

9/4k = [PO4 3-]^5

5th Root of 9/4k = [PO4 3-]?

didn't work, no idea.

n[Ca2+]= 3/2[PO4 3-] actually

Ahh ty. I didn't know if that was actually how to use Ksp values but I figured it was logical.

Good pickup. Can confirm if that gives the correct answer?