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November 08, 2025, 04:02:20 am

Author Topic: Lisachem  (Read 933 times)  Share 

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sam0001

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Lisachem
« on: May 20, 2012, 04:04:21 pm »
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Lisachem 2008 why is the ch2 split into 6 finer peaks in 1 propanol...

...I don't get t, shouldn't it be split into 12?

charmanderp

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Re: Lisachem
« Reply #1 on: May 20, 2012, 04:20:45 pm »
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This is purely from memory, so excuse me if I'm wrong :p

The CH2 is in between a CH3 group and a CH2OH group. Therefore it's adjacent to carbons which in total are themselves directly attached to 5 hydrogen atoms. Using 5+1=6, we could get a sextet.

Why would it be split into 12? There aren't even 12 protons in total in propan-1-ol!
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Nobby

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Re: Lisachem
« Reply #2 on: May 20, 2012, 04:24:46 pm »
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Why would it be split into 12? There aren't even 12 protons in total in propan-1-ol!
In reality it should be 12, because the protons on the CH2 can interact with the three on the CH3, producing 4 fine peaks. But then these 4 peaks can each interact with the two on the other CH2, producing 12 peaks.

But in VCE trial exams and study guides etc. I've only seen the (n+1) generalisation.

sam0001

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Re: Lisachem
« Reply #3 on: May 20, 2012, 04:35:51 pm »
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Nobby, can vcaa test us on molecules such as 1 propanol? I was under the impression that they wouldn't.

charmanderp

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Re: Lisachem
« Reply #4 on: May 20, 2012, 04:42:07 pm »
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They can, but as far as I know they only expect you to know the (n+1) rule. 2009 NEAP Short Answer Question 3.e asks you to draw the high resolution H-NMR spectrum of propan-1-ol and the answer provided has the --CH2-- peak split into six.
« Last Edit: May 20, 2012, 04:54:20 pm by charmanderp »
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sam0001

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Re: Lisachem
« Reply #5 on: May 20, 2012, 04:48:27 pm »
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Brilliant. Thanks for the help!