Chem Questions

[AllAboutTheLGs]

Just remember OIL-RIG

[pi]

Yep, an(ode) oil rig cat(hode) (reads as: an oil rig cat)

[Hutchoo]

I don't really understand the anode-cathode part. I know anode is referring to negative charge and cathode is positive, but I don't get how that works in conjunction with oil rig D;?

//dumbpost

[t35t]

I thought anode and cathode part refers to unit 4 where we describe two cells and where oxidation and reduction take place? (oixidation takes place in the anode, and anions move...towards it?, and reduction takes place in the cathode, and cations move towards it?)
I remember cause I always grouped the vowels and the consonants together, e.g. Anode, Oxidation, Anion and Cathode, Reduction, Cation

anywho I have a question of my own.

If we were asked to "prove" CaSO4.2H2O, by finding out the empirical formula, and hence, that there are two parts of water with one part of CaSO4, when finding the mole of water, would we place it over (18g/mol) or over (36g/mol)?

[aznxD]

I thought anode and cathode part refers to unit 4 where we describe two cells and where oxidation and reduction take place? (oixidation takes place in the anode, and anions move...towards it?, and reduction takes place in the cathode, and cations move towards it?)
I remember cause I always grouped the vowels and the consonants together, e.g. Anode, Oxidation, Anion and Cathode, Reduction, Cation

anywho I have a question of my own.

If we were asked to "prove" CaSO4.2H2O, by finding out the empirical formula, and hence, that there are two parts of water with one part of CaSO4, when finding the mole of water, would we place it over (18g/mol) or over (36g/mol)?

18 as you want to find the mole ratio of CaSO4 to H2O

[pi]

I don't really understand the anode-cathode part. I know anode is referring to negative charge and cathode is positive, but I don't get how that works in conjunction with oil rig D;?

//dumbpost

Unit 4, dw now

[charmanderp]

Yeah split it up and then work out vanadium.