ATARNotes Chemistry Unit 4 Book

[TheRajinator]

Thanks man, I'll buy it once it's available.

[ninwa]

We might also be able to arrange pick up in the Glen Waverley or Caulfield areas, or the state library

[paulsterio]

Thushan might also be able to do a sale at Monash Clayton, cause he's there like every day

[thushan]

Thushan might also be able to do a sale at Monash Clayton, cause he's there like every day

LOL but I don't have stock on me!

[Jenny_2108]

I'm so excited to buy AN Chem tomorrow ^^ Hope it has heaps of questions for me to practise and prepare for the next SAC
Cant wait!!!

[taiga]

Can do sales at Monash Clayton, just PM me.

[kimk2kr]

got my book today

seems really good! hopefully i do really well in the end with this .

thanks thushan

[Jenny_2108]

Hey Thushan, I have some questions about the book

1. In test 3
    Q2a) determine the equilibrium yield of HI in this reaction.
    The ans is 0.316*100/0.4= 79%
    Because the percentage of yield is how much reactants converted to products so I do the other way
     = 0.316(1+127).100/0.2*2+2*127*0.2= 79%
    Is it right or wrong?

    Q2f) the ans: the mark should be awarded if "neither" is circled. But there is no answer given as "neither"
            I think it should be "no change"
   
     Q2g) the ans: Dave's container must be of a higher temperature (...) the reaction is exothermic and at higher temperature K does   
     decrease, hence the yield decreases
     But the question gives that delta H>0 so it should be endothermic and Jo's container must be at higher temperature, not Dave's

2. In test 5
     Q2d) the explanation and the model answer is different?!?
     The sample answer is n(CH3COOH)final=n(CH3COOH)initial-n(CH3COOH)react
                                                                 = 0.505*0.990+n(HCl) ?!?
                                                                 = 0.500-0.0100*10.0=0.600 mol ?!?
 
      The explanation: n(CH3COOH)final=n(CH3COOH)initial+n(CH3COOH) produced
                                                          =0.5+0.01*10=0.600 mol

      Iam so confused when reading the sample answer and the explanation 

[thushan]

Hey Thushan, I have some questions about the book

1. In test 3
    Q2a) determine the equilibrium yield of HI in this reaction.
    The ans is 0.316*100/0.4= 79%
    Because the percentage of yield is how much reactants converted to products so I do the other way
     = 0.316(1+127).100/0.2*2+2*127*0.2= 79%
    Is it right or wrong?

    Q2f) the ans: the mark should be awarded if "neither" is circled. But there is no answer given as "neither"
            I think it should be "no change"
   
     Q2g) the ans: Dave's container must be of a higher temperature (...) the reaction is exothermic and at higher temperature K does   
     decrease, hence the yield decreases
     But the question gives that delta H>0 so it should be endothermic and Jo's container must be at higher temperature, not Dave's

2. In test 5
     Q2d) the explanation and the model answer is different?!?
     The sample answer is n(CH3COOH)final=n(CH3COOH)initial-n(CH3COOH)react
                                                                 = 0.505*0.990+n(HCl) ?!?
                                                                 = 0.500-0.0100*10.0=0.600 mol ?!?
 
      The explanation: n(CH3COOH)final=n(CH3COOH)initial+n(CH3COOH) produced
                                                          =0.5+0.01*10=0.600 mol

      Iam so confused when reading the sample answer and the explanation 

AOS1T3 Q2a) --> Your answer is fine.

AOS1T3 Q2f) --> Thanks, that's what I meant.

AOS1T3 Q2g) --> Mistake already rectified, see errata thread.

AOS1T5 Q2d) --> good spot. it's meant to be:

The sample answer is n(CH3COOH)final=n(CH3COOH)initial+n(CH3COOH)produced
                                                                 = 0.505*0.990+n(HCl) ?!?
                                                                 = 0.500+0.0100*10.0=0.600 mol ?!?

[TheRajinator]

Hey I ordered both the physics and chemistry ATARNOTES books online on the 28th of July. I still haven't received it, just wondering shouldn't I have gotten it by now?

[nisha]

Hey I ordered both the physics and chemistry ATARNOTES books online on the 28th of July. I still haven't received it, just wondering shouldn't I have gotten it by now?

Hmmm, I ordered mine on the 24th of July and I received mine a few days ago. I'm sure it'll come around soon enough, wait a week, and it should be there.

[TheRajinator]

Hey I ordered both the physics and chemistry ATARNOTES books online on the 28th of July. I still haven't received it, just wondering shouldn't I have gotten it by now?

Hmmm, I ordered mine on the 24th of July and I received mine a few days ago. I'm sure it'll come around soon enough, wait a week, and it should be there.

I have almost waited a week, I guess I just have to wait and hope it comes soon...

[thushan]

Hey I ordered both the physics and chemistry ATARNOTES books online on the 28th of July. I still haven't received it, just wondering shouldn't I have gotten it by now?

Hmmm, I ordered mine on the 24th of July and I received mine a few days ago. I'm sure it'll come around soon enough, wait a week, and it should be there.

I have almost waited a week, I guess I just have to wait and hope it comes soon...

Seriously? Lemme just give enwiabe a kick up his lazy ass...

[thushan]

Hey I ordered both the physics and chemistry ATARNOTES books online on the 28th of July. I still haven't received it, just wondering shouldn't I have gotten it by now?

Hmmm, I ordered mine on the 24th of July and I received mine a few days ago. I'm sure it'll come around soon enough, wait a week, and it should be there.

I have almost waited a week, I guess I just have to wait and hope it comes soon...

Seriously? Lemme just give enwiabe a kick up his lazy ass...

Talked to enwiabe. Turns out he had posted it. Looks like I have to kick Australia Post up its ass. Nah, i'll let the rajinator do that

[TheRajinator]

yeah i sent a PM to enwiabe, but do you think it's Australia Post who have failed to send it or enwiabe?