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November 01, 2025, 12:36:36 pm
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Author Topic: acid-base equilibria help  (Read 503 times)  Share 

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rebeckab

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acid-base equilibria help
« on: August 14, 2012, 08:24:35 pm »
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If the Kw at a particular temperature is 10^-12 M^2, determine the pH of
 a) a neutral solution
 b) an acidic solution
 c) a basic solution


I don't really understand what it's asking me to do?
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Phantom-II

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Re: acid-base equilibria help
« Reply #1 on: August 14, 2012, 08:46:27 pm »
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Kw is [H3O+][OH-]
In neutral solution [H3O]=[OH]
so square root 10^-12 gets you [H3O], then -log10 it. pH should = 6 i thnk?
acidic is when [H3O]>[OH], so it would be any pH lower than the one calculated above^
and basic is when it is above 6

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rebeckab

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Re: acid-base equilibria help
« Reply #2 on: August 14, 2012, 09:06:50 pm »
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thanks! I was confused as to whether to give exact values for the acidic/basic solutions, this makes so much more sense :)
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