The sound from a pneumatic drill is 1.0mW m^-2 at a distance of 1.0m. Assume that the sound spreads out equally in all directions.
Watts per sq. metre is the units for intensity.
So the inverse square law:

So if we have

and


and

We know that

and

We can easily get this expression for the ratio between

and

from that
^2)
Sub in and solve for I_2



So the sound intensity
level refers to the decibel scale. We know the sound intensity at 10m, so it's just a matter of subbing in.

is the intensity of the source,

is the intensity of the reference source.
For the decibel scale, the reference intensity is

. Note that if you want to compare the difference between two sound levels, you can sub in I_1 as one intensity, and I_0 as another sound intensity. I'd recommend playing around with the logs laws / subbing in stuff and see what you can get out (you should be able to show what happens for those increase by a factor of 10 etc.)
Anyway: