X-Ray momentum/energy question?

[StumbleBum]

An X-ray source produces X-rays of momentum 5.5x10^-24kgms^-1

What is the energy, in kilo electron volts (keV), of one of these X-rays?

In the answers they used the equations relating to photons, not matter, and got the answer 10.3keV. However it was my understanding that X-rays were matter and therefore you would need to use the deBroglie equations for matter to work it out..?

Can someone please verify which way is correct, either mine or the answers, and if the answers why so?

[paulsterio]

X-Rays are a form of electromagnetic radiation, i.e. they are a form of light (specifically they are highly energetic with high frequencies).

Thus, they are, essentially, photons, which is why you use the equations for light. So yeah, the answers are correct.

[StumbleBum]

X-Rays are a form of electromagnetic radiation, i.e. they are a form of light (specifically they are highly energetic with high frequencies).

Thus, they are, essentially, photons, which is why you use the equations for light. So yeah, the answers are correct.

Alright cheers, that clears things up!

[StumbleBum]

Alright, i have another question...

A 4WD enthusiast has fitted a communications two way radio with an aerial on the front bull bar so as to remain safely in contact when travelling in remote areas.

The aerial is vertically mounted and 1.2m long from the base to tip.

As the vehicle travels due East on a level road a voltage difference is induced across the ends of the aerial.

Which of the tip or the base of the aerial is the positive end of the voltage difference? Explain your reasoning.


Also what is the difference between electron flow and conventional current?

[sahil26]

Alright, i have another question...

A 4WD enthusiast has fitted a communications two way radio with an aerial on the front bull bar so as to remain safely in contact when travelling in remote areas.

The aerial is vertically mounted and 1.2m long from the base to tip.

As the vehicle travels due East on a level road a voltage difference is induced across the ends of the aerial.

Which of the tip or the base of the aerial is the positive end of the voltage difference? Explain your reasoning.


Also what is the difference between electron flow and conventional correct?

I might be wrong about the first question so can someone please confirm if i am current?

Right- hand slap rule ( you might know it differently) has to be used for this question.
The magnetic field on earth goes from the south pole to the north pole ( don't get confused by this. In magnets, it is ALWAYS north to south).
The vehicle is travelling due east.
Hence your fingers point north and your palm is in the easterly direction.
The thumb points downwards hence the tip of the aerial is positive.

Correct me if i am wrong though. I have a confused perception of this.

Electron flow is the movement of negatively charged electrons. Negative to positive electrode.
Conventional Current flow is the flow of positive charges (protons don't movement. Due to the fact that negative charges flow in one direction.. we can imagine as positive charges flowing in the other). Positive to Negative electrode.