Author Topic: Any Analysis Questions Please :) (Read 1092 times) Tweet Share

TheOverAchiever · « **on:** October 30, 2012, 10:32:53 pm »

Hey guys, can you all pelase post some questions you find challenging from any exam/book to practice?

Mr Newton · « **Reply #1 on:** October 30, 2012, 11:52:16 pm »

heres a matrices one..

brenden · « **Reply #2 on:** October 31, 2012, 12:40:35 am »

Quote from: Mr Newton on October 30, 2012, 11:52:16 pm

heres a matrices one..

I'd play with this on my calculator for ten minutes LOL

paulsterio · « **Reply #3 on:** October 31, 2012, 12:43:15 am »

Ahh, the recognition required there is that if XY = YX then, X and Y will have to be inverses.

Thus, find the inverse of X and you will see that the top left hand element will be $\frac{a}{a^2-b^2}$

Yendall · « **Reply #4 on:** October 31, 2012, 12:00:07 pm »

Quote from: Paul Stereo on October 31, 2012, 12:43:15 am

Ahh, the recognition required there is that if XY = YX then, X and Y will have to be inverses.

Thus, find the inverse of X and you will see that the top left hand element will be $\frac{a}{a^2-b^2}$

So the product would be $Y^-^1 * X^-^1$ ?

If so, wouldn't $t = \frac {w}{t*w-u*v}$

I see that $\begin{bmatrix} a & b \\ b & a \end{bmatrix}$ inversed would equal $\begin{bmatrix} \frac{a}{a^2-b^2} & \frac{-b}{a^2-b^2}\\ \frac{-b}{a^2-b^2} & \frac{a}{a^2-b^2} \end{bmatrix}$

But wouldn't that be for element 1,1 of X (a), rather than element 1,1 of Y (t)

StumbleBum · « **Reply #5 on:** October 31, 2012, 12:40:42 pm »

Quote from: Yendall on October 31, 2012, 12:00:07 pm

So the product would be $Y^-^1 * X^-^1$ ?

I think he ment that they will be the inverse of each other, so $Y^-^1 = X$ and $X^-^1 = Y$

Yendall · « **Reply #6 on:** October 31, 2012, 12:42:33 pm »

Quote from: StumbleBum on October 31, 2012, 12:40:42 pm

Quote from: Yendall on October 31, 2012, 12:00:07 pm
So the product would be $Y^-^1 * X^-^1$ ?

I think he ment that they will be the inverse of each other, so $Y^-^1 = X$ and $X^-^1 = Y$

Ohhhh i see how that works. Makes sense

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Author Topic: Any Analysis Questions Please :) (Read 1092 times) Tweet Share

TheOverAchiever

Any Analysis Questions Please :)

Mr Newton

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brenden

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paulsterio

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Yendall

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StumbleBum

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Yendall

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