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November 01, 2025, 10:24:16 am
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Author Topic: question3 vcaa 2010  (Read 632 times)  Share 

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nooshnoosh95

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question3 vcaa 2010
« on: November 01, 2012, 06:13:07 pm »
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on exam 1 i dont get how they got 2 degrees as the standard deviation
i did the range (approx 186-173) over 6 only because that seemed logical but is there an actual rule?
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dfgjgddjidfg

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Re: question3 vcaa 2010
« Reply #1 on: November 01, 2012, 06:16:53 pm »
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that is basically the rule for normal distributions. Range/6. but you could also start at the mean(same as median for symmetrical distributions) and move 34% to the left or right of the mean which is equal to 1 SD away from the mean
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Stick

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Re: question3 vcaa 2010
« Reply #2 on: November 01, 2012, 06:18:58 pm »
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Yeah, what you did is the logical rule: range/6. When the data is symmetrical, you use this formula. However, use range/4 if the shape of the data is skewed or unknown. :)
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nooshnoosh95

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Re: question3 vcaa 2010
« Reply #3 on: November 01, 2012, 06:20:24 pm »
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okay cool
thanks guys! :)
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