2010 VCAA Exam 1 Quickie.

[abcdefghi]

Question 3.

How do you get the standard deviation or the 68-95-99.7 from just looking at the graph/boxplot. Am I missing something here?

http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf

pls halp.

edit: question 3, not 4

[Felicity Wishes]

You don't need the SD. Are you talking about the multiple choice?

[abcdefghi]

You don't need the SD. Are you talking about the multiple choice?

Yeah, I don't know what the fuck I need. I just don't know how to get it.

Also it was question 3, not 4. Sorry.

[oneialex]

Neither are needed. Simply look at the Y-axis, which reveals the percentages for each section on the graph. For example, the 'no car' section is between (roughly) 74 and 88 percent, therefore taking up 14% of the graph.

*Edit* my bad, the above analysis was on Question 4.

[Felicity Wishes]

You don't need the SD. Are you talking about the multiple choice?

Yeah, I don't know what the fuck I need. I just don't know how to get it.

Also it was question 3, not 4. Sorry.

Sorry. I was talking about 4. What was the answer? I said B assuming that that 180 was the mean.

[StumbleBum]

You don't need the SD. Are you talking about the multiple choice?

Yeah, I don't know what the fuck I need. I just don't know how to get it.

Also it was question 3, not 4. Sorry.

No need to swear champ.
Because they have stated to use the 68-95-99.7 rule, you can assume that it is a normal distribution. Hence, as majority of the data will lie within three SD's from the mean, it can be said that:

  (By the way, this is an actual rule for normally distributed data)

So, it would be so the answer is B.

[billyjackson768]

You look at your picture of a bell curve which shows what percentage of data lies within each section and guesstimate. 

For me I just drew some lines around the mean where the 64% would lie, then the 95 and 99.7 and it turns out each line, which should represent a standard deviation was 2 apart. So that was my answer, 2.

[abcdefghi]

You don't need the SD. Are you talking about the multiple choice?

Yeah, I don't know what the fuck I need. I just don't know how to get it.

Also it was question 3, not 4. Sorry.

No need to swear champ.
Because they have stated to use the 68-95-99.7 rule, you can assume that it is a normal distribution. Hence, as majority of the data will lie within three SD's from the mean, it can be said that:



So, it would be so the answer is B.

Yes because I was really having a go at her. Nice one. We're all 16-18 here, wow.

Thanks anyway.

[Felicity Wishes]

You don't need the SD. Are you talking about the multiple choice?

Yeah, I don't know what the fuck I need. I just don't know how to get it.

Also it was question 3, not 4. Sorry.

No need to swear champ.
Because they have stated to use the 68-95-99.7 rule, you can assume that it is a normal distribution. Hence, as majority of the data will lie within three SD's from the mean, it can be said that:



So, it would be so the answer is B.

Yes because I was really having a go at her. Nice one. We're all 16-18 here, wow.

Thanks anyway.

Calm ya farm.

[StumbleBum]

Yes because I was really having a go at her. Nice one. We're all 16-18 here, wow.

Thanks anyway.

HAHA, I wasn't having a go at you, i just didn't see the point in swearing. It really wasn't necessary.