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November 08, 2025, 08:22:35 am

Author Topic: 2010 vcaa exam  (Read 639 times)  Share 

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Teen

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2010 vcaa exam
« on: November 06, 2012, 12:54:56 pm »
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Let x be a normally distributed random variable with mean of 5 and variance of 9 and let z be the random variable with the standard normal distribution

Find b such that that pr(x>7)=pr(z,b)
I am getting positive 1.5 but the answer is - 1.5 why ?

Thanks in advance
2011-biology
2012-Aiming  for ATAR of 90+

BubbleWrapMan

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Re: 2010 vcaa exam
« Reply #1 on: November 06, 2012, 12:56:30 pm »
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Typo?
Tim Koussas -- Co-author of ExamPro Mathematical Methods and Specialist Mathematics Study Guides, editor for the Further Mathematics Study Guide.

Current PhD student at La Trobe University.

Reckoner

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Re: 2010 vcaa exam
« Reply #2 on: November 06, 2012, 01:26:31 pm »
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Is this 5.b on exam 1?

The question is find b when

So using the formula

Where

We get

However, the the question asks for . The value we got was when .

So through the symmetry of the normal distribution curve,

Here's the graph from the assessment report showing the symmetry of the areas of distribution. 




 

Teen

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Re: 2010 vcaa exam
« Reply #3 on: November 06, 2012, 02:05:48 pm »
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Thanks ;)
2011-biology
2012-Aiming  for ATAR of 90+