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November 01, 2025, 01:04:45 pm

Author Topic: Question about diluting acidic solution.  (Read 870 times)  Share 

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Minimalist

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Question about diluting acidic solution.
« on: November 10, 2012, 10:10:53 pm »
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Not sure if this is on the course, but if you have 10mL 6pH solution if HCl and and dilute it to 1000mL, what is the new pH? Thanks

dfgjgddjidfg

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Re: Question about diluting acidic solution.
« Reply #1 on: November 10, 2012, 10:42:58 pm »
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approximately 8

Shenz0r

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Re: Question about diluting acidic solution.
« Reply #2 on: November 10, 2012, 10:46:55 pm »
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You diluted it by a factor of 100, so you move two units up, giving a new pH of 8. This only works for strong acids though.
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Minimalist

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Re: Question about diluting acidic solution.
« Reply #3 on: November 10, 2012, 11:06:36 pm »
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But 8 implies it's basic... surely that's not possible??

emiinaaa

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Re: Question about diluting acidic solution.
« Reply #4 on: November 10, 2012, 11:36:03 pm »
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Because the HCl is present in the solution at such a low concentration (10-6), the main reaction occuring in that beaker or whatever is the self ionisation of water rather than the HCl + H2O --> H3O+ + OH- reaction, making it essentially neutral, ie. pH close to 7.
I may be wrong, but this is how a similiar question that I've done was approached.

kenhung123

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Re: Question about diluting acidic solution.
« Reply #5 on: November 11, 2012, 01:31:27 am »
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But 8 implies it's basic... surely that's not possible??
Remember the definition of an acidic and basic solution is based on the relative amounts of protons in relation to the hydroxides

sin0001

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Re: Question about diluting acidic solution.
« Reply #6 on: November 11, 2012, 08:59:18 am »
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pH will approach 7, but won't pass it imo
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