Emergency chemostry question

[HERculina]

Currently furiously cramming for this chem exam, and came across this question:
To determine the heat capacity of a bomb calorimeter a student adds 140g of water at 50.0 degrees celcius to the bomb, thich is initially at 25 degrees celcius. The final temperature is 32.0 degrees celsius. What is the heat capacity of the calorimeter in joules per degree celcius?
How on earth do u work this out?
Thanks.

ANS: 1.51 x 10^3 J/degrees celcius

[Phy124]

E = 4.184 x m x Δt (where Δt is the change in water temperature and m is the mass of water added, in grams)
= 4.184 x 140 x 18 = 4100.32 J

Heat Capacity  = E/Δt (where Δt is the change in colorimeter temperature)
= 4100.32/7 = 1506.24 = 1.51 x 10³ J/°C