Parallel Circuits...

[Try_Beast]

Just to confirm, if there are three parallel wires, all of which are connected to a battery source, that have a certain number of globes in each of them...and one of the globes in one of the wires breaks/stops functioning..then only the globes in that wire will stop working right?

But what about the brightness of the other globes in the other two wires..will they have the same brightness or be brighter than before?? Please explain thoroughly, thankss.

[StumbleBum]

Just to confirm, if there are three parallel wires, all of which are connected to a battery source, that have a certain number of globes in each of them...and one of the globes in one of the wires breaks/stops functioning..then only the globes in that wire will stop working right?

Yes, only the globes that are in the wire with the blown globe will stop working.

But what about the brightness of the other globes in the other two wires..will they have the same brightness or be brighter than before?? Please explain thoroughly, thankss.

The globes would now glow brighter because they will receive more current than before according to the formulae:



So if you remove one of the branches of the parallel circuit the    and    will now have to be larger to account for the    that has to stay the same.

EDIT: That's wrong, my memory of electricity is shoddy to say the least.

[haider543]

are you sure? because every question ive done like this,in the answer the brightness of the other rows stays the same once one row is not working anymore, because the voltage will still be the same in the working rows after the one row is blown, hence current is the same?

[nerfsdacier]

Voltage stays same, I always thought total current would decrease as you are increasing effective resistance. However I think that the haider is right, the brightness should stay the same...

P = VI = V^2/R, both V and R stay same, so brightness stay the same.
I could be wrong, it's been a while haha

[availn]

Batteries don't always give a constant current. If you remove a light bulb, then the combined current drawn by the remaining bulbs will be less.

A bulb will have a power rating, P. In parallel, the voltage going through a bulb is always the same, and P = V^2/R, so the resistance of the bulb will remain constant for that voltage. If you remove a bulb, you are adding total resistance to the circuit, as the loads are wired in parallel, so you will draw less current for each bulb removed.