Login

Welcome, Guest. Please login or register.

November 01, 2025, 11:36:58 am

Author Topic: Chemistry 3/4 2013 Thread  (Read 448755 times)  Share 

0 Members and 1 Guest are viewing this topic.

hardworker

  • Victorian
  • Trendsetter
  • **
  • Posts: 147
  • I'll try being nicer when you try being smarter.
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #570 on: March 04, 2013, 09:44:18 pm »
0
If Carbonic acid reacts with a base of sodium carbonate which is the one in excess. 

H2CO3+Na2CO3 ARROW Na2CO3+H20+CO2
2012 Psychology
2013 Maths Methods Biology Chemistry Further Maths English

teletubbies_95

  • Victorian
  • Forum Leader
  • ****
  • Posts: 691
  • heartbreaker <3 JB
  • Respect: +24
  • School: Mac.Rob
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #571 on: March 04, 2013, 09:54:52 pm »
+1
Hey guyss! :) Great questions everyone! and wishing you the best of luck for all your sacs! :)

I have a question which is attached?
How do you determine the mole ratio between MgSO4.7H20 and MgNH4PO4.6H20?


Thanks ! :)
2012: Psychology(46) Biology (44)
2013: Chem(41)---EngLang(44)--HealthnHuman(47)---Methods(41)--DEAKIN PSYCH(4.5)
ATAR=99.10! :) umat=94ile
i liek lala :) arre bhaiya aal izz well :) <3

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #572 on: March 05, 2013, 06:06:53 pm »
0
Thanks for the reply :D

Got a few other questions: calc the mass of anhydrous sodium carbonate required to make 250ml of a 0.1M solution.
Don't quite know how to approach that one^


Conic

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 427
  • Very eccentric.
  • Respect: +42
Re: Chemistry 3/4 2013 Thread
« Reply #573 on: March 05, 2013, 06:12:56 pm »
0
Thanks for the reply :D

Got a few other questions: calc the mass of anhydrous sodium carbonate required to make 250ml of a 0.1M solution.
Don't quite know how to approach that one^
250mL = 0.25L



2012-13: VCE at Parade College (Chemistry, English, Mathematical Methods, Physics and Specialist Mathematics).
2014-16: Bachelor of Science at La Trobe University (Mathematics and Statistics).
2017-17: Bachelor of Science (Honours) at La Trobe University (Mathematics).
2018-21: PhD at La Trobe University (Mathematics).

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #574 on: March 05, 2013, 06:15:45 pm »
0
250mL = 0.25L





Wow that was a quick reply! It makes sense now I realised I'd written one
Of the numbers wrong! :/

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #575 on: March 05, 2013, 08:24:21 pm »
0
Last question and I've completely finished this sheet! But i need help : Determine the number of mol of chloride ions in a 10gram sample of HCL ! I use n=m/mr right? but it still not working out :S
Cheers in advance

Jeggz

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 493
  • Respect: +42
  • School: Presbyterian Ladies' College
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #576 on: March 05, 2013, 08:27:50 pm »
0
Is the answer 0.33?
« Last Edit: March 05, 2013, 08:36:37 pm by myuraa »
Melbourne University - Commerce; Actuarial Studies.

Tutoring 2015 - Email/PM for places!

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #577 on: March 05, 2013, 08:30:24 pm »
0
how'd you get that??

Jeggz

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 493
  • Respect: +42
  • School: Presbyterian Ladies' College
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #578 on: March 05, 2013, 08:35:57 pm »
0
how'd you get that??

Well you're thoughts were perfectly correct  :)
You know that mass (HCl) = 10 grams
Hence the n(HCl) = 12/Mr , the Molar mass of HCL is 35.5+1 = 36.5
Hence, n(Hcl) = 0.33 and the Moles of Hydrogen = Moles of Cl due to 1:1 ratio
Melbourne University - Commerce; Actuarial Studies.

Tutoring 2015 - Email/PM for places!

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #579 on: March 05, 2013, 08:58:44 pm »
0
Well you're thoughts were perfectly correct  :)
You know that mass (HCl) = 10 grams
Hence the n(HCl) = 12/Mr , the Molar mass of HCL is 35.5+1 = 36.5
Hence, n(Hcl) = 0.33 and the Moles of Hydrogen = Moles of Cl due to 1:1 ratio
yeah that works but where'd you get the 12 from? :)
thanks btw

Jeggz

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 493
  • Respect: +42
  • School: Presbyterian Ladies' College
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #580 on: March 05, 2013, 09:07:33 pm »
0
yeah that works but where'd you get the 12 from? :)
thanks btw

OMG SORRY! haha, I meant 10/Mr!  :)
Melbourne University - Commerce; Actuarial Studies.

Tutoring 2015 - Email/PM for places!

justsoundslikeaworn-outcliche

  • Victorian
  • Trailblazer
  • *
  • Posts: 33
  • Respect: 0
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #581 on: March 05, 2013, 09:16:09 pm »
0
haha thats okay!wait so the mol for hcl is the same for the chloride ions in it?

Jeggz

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 493
  • Respect: +42
  • School: Presbyterian Ladies' College
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #582 on: March 05, 2013, 09:27:21 pm »
+2
haha thats okay!wait so the mol for hcl is the same for the chloride ions in it?

Yup exactly! It's because of the 1:1 ratio between Hydrogen and Chloride. If that makes sense!
For example if it was like H2SO4, then the mole ratio between Hydogen and Sulfate is 2:1 and hence the mole of Sulfate ions would be half the number of Hydrogen mole.
Melbourne University - Commerce; Actuarial Studies.

Tutoring 2015 - Email/PM for places!

academicbulimia

  • Victorian
  • Trendsetter
  • **
  • Posts: 159
  • Respect: +4
  • School: some really crap country school
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #583 on: March 07, 2013, 06:30:24 pm »
0
hey i'd just like some help on a few chem questions i'm having trouble with. We did a practice sac today with the analysis of brick cleaner in prep for the fertilizer analysis sac next week, we used a brick cleaner that was 32% hcl, got 5ml of this brick cleaner and  diluted this with distilled water, and then used a 20ml sample of this and used  and 0.1 AgNO3 as the titre to be titred into the brick cleaner sample, a precipitate formed we then filtered this with a vacuum pump, and lastly we dried it overnight to find the end product of a sample of 2.945g AgCl.

how would i determine the no of mol, of chloride ions in the undiluted sample of brick cleaner?

and the mass of hcl in the original sample?
thanks in advance!!!
« Last Edit: March 07, 2013, 06:44:12 pm by academicbulimia »
2012: Psychology~Biology
2013:Chem~Methods~BusinessManagment~English
[UMAT 96%tile]

academicbulimia

  • Victorian
  • Trendsetter
  • **
  • Posts: 159
  • Respect: +4
  • School: some really crap country school
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #584 on: March 07, 2013, 08:39:18 pm »
0
hate to be a drag but i kinda need urgent help because these questions^ are due tomorrow :s
2012: Psychology~Biology
2013:Chem~Methods~BusinessManagment~English
[UMAT 96%tile]