Login

Welcome, Guest. Please login or register.

November 01, 2025, 11:33:17 am

Author Topic: Chemistry 3/4 2013 Thread  (Read 448755 times)  Share 

0 Members and 1 Guest are viewing this topic.

lzxnl

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3432
  • Respect: +215
Re: Chemistry 3/4 2013 Thread
« Reply #1320 on: September 04, 2013, 11:45:10 pm »
0
I gave an ionic equation above for the dissolution of sulfuric acid.
2012
Mathematical Methods (50) Chinese SL (45~52)

2013
English Language (50) Chemistry (50) Specialist Mathematics (49~54.9) Physics (49) UMEP Physics (96%) ATAR 99.95

2014-2016: University of Melbourne, Bachelor of Science, Diploma in Mathematical Sciences (Applied Maths)

2017-2018: Master of Science (Applied Mathematics)

2019-2024: PhD, MIT (Applied Mathematics)

Accepting students for VCE tutoring in Maths Methods, Specialist Maths and Physics! (and university maths/physics too) PM for more details

achre

  • Victorian
  • Forum Leader
  • ****
  • Posts: 734
  • Respect: +72
Re: Chemistry 3/4 2013 Thread
« Reply #1321 on: September 05, 2013, 06:29:06 pm »
0
Hey all.
Are there any suggested responses for the new study design sample exam on the VCAA website? (VCAA produced or otherwise)

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1322 on: September 05, 2013, 10:44:42 pm »
0
Is there a possibility we could be asked to determine avogadro's number from experimental data on a VCAA exam???? I came across a checkpoints question and had NO idea on what to do  :o
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


Jeggz

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 493
  • Respect: +42
  • School: Presbyterian Ladies' College
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1323 on: September 05, 2013, 10:46:25 pm »
0
Is there a possibility we could be asked to determine avogadro's number from experimental data on a VCAA exam???? I came across a checkpoints question and had NO idea on what to do  :o

We had to determine the Avogadro's number in Faraday, if that's what you're referring to?
Melbourne University - Commerce; Actuarial Studies.

Tutoring 2015 - Email/PM for places!

lzxnl

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3432
  • Respect: +215
Re: Chemistry 3/4 2013 Thread
« Reply #1324 on: September 05, 2013, 10:48:12 pm »
0
Is there a possibility we could be asked to determine avogadro's number from experimental data on a VCAA exam???? I came across a checkpoints question and had NO idea on what to do  :o

What was the question?
2012
Mathematical Methods (50) Chinese SL (45~52)

2013
English Language (50) Chemistry (50) Specialist Mathematics (49~54.9) Physics (49) UMEP Physics (96%) ATAR 99.95

2014-2016: University of Melbourne, Bachelor of Science, Diploma in Mathematical Sciences (Applied Maths)

2017-2018: Master of Science (Applied Mathematics)

2019-2024: PhD, MIT (Applied Mathematics)

Accepting students for VCE tutoring in Maths Methods, Specialist Maths and Physics! (and university maths/physics too) PM for more details

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1325 on: September 05, 2013, 10:53:11 pm »
0
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


Lasercookie

  • Honorary Moderator
  • ATAR Notes Legend
  • *******
  • Posts: 3167
  • Respect: +326
Re: Chemistry 3/4 2013 Thread
« Reply #1326 on: September 05, 2013, 11:03:06 pm »
0
Hey all.
Are there any suggested responses for the new study design sample exam on the VCAA website? (VCAA produced or otherwise)
By the Chemistry Education Assoc. http://www.cea.asn.au/sites/default/files/sample_paper_answers_2013_0.pdf
I don't remember if there was an AN user that produced their own set of solutions either, might be floating around somewhere (not sure).

Some of the questions on the sample exam were from previous VCAA exams too

SocialRhubarb

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 313
  • Respect: +34
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1327 on: September 05, 2013, 11:18:44 pm »
-1
Is there a possibility we could be asked to determine avogadro's number from experimental data on a VCAA exam???? I came across a checkpoints question and had NO idea on what to do  :o

Question doesn't seem to out there. I'm not familiar with the specifics of the course design though.

Avogadro's constant just describes the number of atoms per mole.

Calculate the number of moles of copper that are formed from the mass and molar mass of copper, then work out how many atoms of copper are produced, based on how many electrons are required, remembering that each copper atom requires two electrons. The ratio between the number of copper atoms and the number of moles of copper is Avogadro's constant.
Fight me.

barydos

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 314
  • Respect: 0
  • School: Nossal High School
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1328 on: September 10, 2013, 10:38:29 am »
0
Why do some redox reactions use the OH- electrolyte rather than H+?
And when do we know to balance using OH?
2012: Methods [47] | Chinese SL [35]
2013: Specialist [48] | Chemistry [41] | Physics [44] | English Language [40]
ATAR: 99.55

jgoudie

  • Victorian
  • Trendsetter
  • **
  • Posts: 138
  • Chemisode: an app for studying chemistry
  • Respect: +3
Re: Chemistry 3/4 2013 Thread
« Reply #1329 on: September 10, 2013, 10:57:04 am »
+1
H+ is used when the solution is neutral or acidic, OH- is used when the conditions are alkaline, such as a alkaline battery.  I am pretty sure i have not seen this other than in a multiple choice practice paper.  But if you want to know how to do it normally check below: 

http://www.chemguide.co.uk/inorganic/redox/equations2.html

A very clear to follow set of instructions as always from chemguide.co.uk.


Why do some redox reactions use the OH- electrolyte rather than H+?
And when do we know to balance using OH?
Chemisode: A podcast, iPhone/iPad app for studying VCE chemistry.

Search the appstore: "Chemisode"
http://www.facebook/chemisode34
http://www.facebook/chemisode12
http://jgoudie.podomatic.com/
http://www.youtube.com/mrjasongoudie
Iphone and Ipad apps: 'Chemisode' out in the app store now!

chemdeath

  • Victorian
  • Trailblazer
  • *
  • Posts: 45
  • Respect: 0
  • School: a crap one
Re: Chemistry 3/4 2013 Thread
« Reply #1330 on: September 10, 2013, 04:07:40 pm »
0
Can anyone help me with this attached question, the reaction occurred in a calorimeter?

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1331 on: September 10, 2013, 05:12:41 pm »
+1
Can anyone help me with this attached question, the reaction occurred in a calorimeter?
I'm assuming they're exothermic? I know HCl and NaOH is, and also the Mg reaction producing heat? If you look at the graph for an exothermic reaction/energy profile, the energy released is greater the rise that you see is the energy required to break the bonds in the reactants, the Ea (activation energy), BUT! this is then released as the curve comes back down to the same level as you started, then it drops even further to produce a negative delta H/change in enthalpy. Recap: you absorb let's say 1 unit of energy as Ea, this is then released, so you're back to zero, but then the reaction, being exothermic, releases even more energy so in effect you release more energy than you take in. :)
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1332 on: September 10, 2013, 05:24:07 pm »
+1
I'm reading the instructions for the hydrogen oxygen fuel cell prac I have coming up, in the textbook it implies fuel cells are a glorified electrochemical cell with spontaneous redox reactions occurring to produce electricity, why do we have to connect it to a DC power supply, if its purpose is to generate electricity as a fuel cell??? why are we using electricity here  :o
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


chemdeath

  • Victorian
  • Trailblazer
  • *
  • Posts: 45
  • Respect: 0
  • School: a crap one
Re: Chemistry 3/4 2013 Thread
« Reply #1333 on: September 10, 2013, 05:32:12 pm »
0
I'm assuming they're exothermic? I know HCl and NaOH is, and also the Mg reaction producing heat? If you look at the graph for an exothermic reaction/energy profile, the energy released is greater the rise that you see is the energy required to break the bonds in the reactants, the Ea (activation energy), BUT! this is then released as the curve comes back down to the same level as you started, then it drops even further to produce a negative delta H/change in enthalpy. Recap: you absorb let's say 1 unit of energy as Ea, this is then released, so you're back to zero, but then the reaction, being exothermic, releases even more energy so in effect you release more energy than you take in. :)

Thanks that makes sense, KNO3 is endothermic though?

And one more question for a reaction between 50ml 1M hcl and 50ml naoh the energy change was found to be 2528.9J. Find delta h
Cheers :)

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1334 on: September 10, 2013, 05:37:44 pm »
+1
Thanks that makes sense, KNO3 is endothermic though?

And one more question for a reaction between 50ml 1M hcl and 50ml naoh the energy change was found to be 2528.9J. Find delta h
Cheers :)
For KNO3, the energy absorbed is more than released, as the delta H is positive and you have to gain energy overall.
We need it in kJ/mol. So (2528.9/1000)kJ/(1.0M*0.05L)=50.58kJ/mol. As it is exothermic delta H is negative, and assuming the reaction is the normal 1:1 mol ratio then delta H=-50.58kJ/mol for HCl+NaOH-->NaCl+H2O
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne