Another query

[Thymaster]

F(x)=1/x^2
state the maximal domain and range of the function  y=f(x-a/2)+b
where a and b are >0

[Jaswinder]

Is the answer domain  r/{a} range r/{b}

[Hancock]

Therefore, the denominator can't equal zero. We can find the vertical asymptote by setting it to zero however.

So:
Domain:

As x gets very very large, will approach zero. Therefore, y will approach b but never get there.

Range: