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November 01, 2025, 05:40:08 pm
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Author Topic: Z=x+yi  (Read 736 times)  Share 

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samsiexD

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Z=x+yi
« on: March 25, 2013, 06:12:00 pm »
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Which one is in the form of z=x+yi?

A). x(x^4-10x^2y^2+5y^4)+(5x^4y-10x^2y^3+y^5)i
Or
B). x(x^4-10x^2y^2+5y^4)+(5x^4-10x^2y^2+y^4)yi
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BubbleWrapMan

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Re: Z=x+yi
« Reply #1 on: March 25, 2013, 06:24:45 pm »
+1
Both of them?
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Tim Koussas -- Co-author of ExamPro Mathematical Methods and Specialist Mathematics Study Guides, editor for the Further Mathematics Study Guide.

Current PhD student at La Trobe University.

samsiexD

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Re: Z=x+yi
« Reply #2 on: March 25, 2013, 09:09:52 pm »
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So if x(x^4-10x^2y^2+5y^4)+(5x^4-10x^2y^2+y^4)yi=1, equating the imaginary parts to get an equation in x and y would give me (5x^4-10x^2y^2+y^4)y=1?
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BubbleWrapMan

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Re: Z=x+yi
« Reply #3 on: March 26, 2013, 05:27:46 pm »
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The imaginary part of 1 is 0, so you get (5x^4-10x^2y^2+y^4)y = 0 and x(x^4-10x^2y^2+5y^4) = 1, assuming x and y are real.
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Tim Koussas -- Co-author of ExamPro Mathematical Methods and Specialist Mathematics Study Guides, editor for the Further Mathematics Study Guide.

Current PhD student at La Trobe University.
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