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VCE Physics Question Thread!
Coolmate:
--- Quote from: Roger Luo on March 26, 2021, 06:40:16 pm ---I am quite ahead for physics, and don't know what to do, right now I am done in Unit 3 for physics, but our school is only halfway through it, should I start revising practice exams for unit 3, or get the other jacaranda book and do the questions of that. tbh, I don't know how to juggle Unit 3 review with stronger SAC prep.
--- End quote ---
Hey Roger Luo!
Welcome to the forums :)
It is great that you are ahead for VCE Physics, I didn't do VCE Physics, but I do strongly suggest starting practice questions early. The thing that really helped me during my HSC was applying the content to questions, rather than straight memorisation as you can get any question on the day.
If you run out of questions from past VCE papers, you could go through past HSC papers here and here and sort out any relevant questions to the VCE syllabus.
Good luck with everything :)
Coolmate 8)
ErnieTheBirdi:
I need help... I've been hitting the fan with physics recently. Getting 49% ( still pass) and a 50% on the first two AOS so far for U3... Am I screwed if I want a good study score? like Raw 35+? HELP ME :'( :'( :'( :'( :'( :'(
Samueliscool223:
Why is answer A here wrong (q. 12)? isnt the velocity function a linear equation for objects falling under the influence of gravity, and hence isnt the speed of da object increasing at a constant rate? i wouldve thought both A and C are correct but apparently its just C
Rachelrachel:
Hey guys, I'm completing some Unit 1&2 conservation of momentum questions and am really confused by this one.
"a railway wagon of mass 2.5 tonnes moving along a horizontal track at 2 m/s runs into a stationary engine and is coupled to it. After the collision, the engine and the wagon move off at 0.3 m/s. What is the mass of the engine alone?"
I used this formula:
m1u1 + m2u2 = m3v3
to obtain:
2.5*2+0 = (2.5+m)*0.3
This resulted in m=14.17 tonnes. However, my textbook says that 4.2 tonnes is correct. I have no idea how to obtain this answer.
Can anyone offer any insight?
ArtyDreams:
--- Quote from: Rachelrachel on July 25, 2021, 05:34:02 pm ---Hey guys, I'm completing some Unit 1&2 conservation of momentum questions and am really confused by this one.
"a railway wagon of mass 2.5 tonnes moving along a horizontal track at 2 m/s runs into a stationary engine and is coupled to it. After the collision, the engine and the wagon move off at 0.3 m/s. What is the mass of the engine alone?"
I used this formula:
m1u1 + m2u2 = m3v3
to obtain:
2.5*2+0 = (2.5+m)*0.3
This resulted in m=14.17 tonnes. However, my textbook says that 4.2 tonnes is correct. I have no idea how to obtain this answer.
Can anyone offer any insight?
--- End quote ---
Hi! Your working out is correct but you have to make sure that you convert the tonnes to kilograms. In the formula p=mv, mass is in kilograms and v is in m/s, to get your momentum being kg/m/s. Hope this helps!
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