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October 21, 2025, 08:16:00 pm

Author Topic: Just need a quick explenation ! ( Integrals)  (Read 758 times)  Share 

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ArthurJ

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Just need a quick explenation ! ( Integrals)
« on: May 02, 2013, 11:04:44 pm »
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∫_a^b▒〖f(x)-g(x)〗  , so I understand that this will give me the area between two curves between two certain points.

However, I’m just unsure as to how I deal with problems that go under the x axis. I don’t seem to get the right answer, is it because it’s a negative area?
If so do I just do -∫_a^b▒〖f(x)-g(x)〗  ?
We only learnt it today, but yea any help would be much appreciated!

ArthurJ

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Re: Just need a quick explenation ! ( Integrals)
« Reply #1 on: May 02, 2013, 11:05:43 pm »
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the _a^b▒ was ment to be the upper bound and lower bound but my icon stuff is playing up :/

Alwin

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Re: Just need a quick explenation ! ( Integrals)
« Reply #2 on: May 03, 2013, 07:49:55 pm »
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∫_a^b▒〖f(x)-g(x)〗  , so I understand that this will give me the area between two curves between two certain points.

However, I’m just unsure as to how I deal with problems that go under the x axis. I don’t seem to get the right answer, is it because it’s a negative area?
If so do I just do -∫_a^b▒〖f(x)-g(x)〗  ?
We only learnt it today, but yea any help would be much appreciated!

It doesn't matter whether the graphs of f(x) and g(x) are above, or below the x axis. the only thing that matters is which one is above the other, ie if f(x)>g(x) then do f(x) - g(x) in the integral. Otherwise, if g(x)>f(x) then you must do g(x)-f(x).

What problem were you having difficulty with getting the right answer?
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brightsky

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Re: Just need a quick explenation ! ( Integrals)
« Reply #3 on: May 03, 2013, 08:38:46 pm »
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just memorise the following formula:

area = int^(right bound)_(left bound) (top curve - bottom curve) dx

it's also good to understand why it doesn't matter whether the graphs are below, above or straddling the x-axis. consider all possible cases and work the answer out from 'scratch'.
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