Login

Welcome, Guest. Please login or register.

November 08, 2025, 09:43:43 am

Author Topic: Complex Numbers: u = i^5z is found by...  (Read 692 times)  Share 

0 Members and 1 Guest are viewing this topic.

ahat

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 282
  • Monash MBBS class of 2018!
  • Respect: +9
  • School Grad Year: 2013
Complex Numbers: u = i^5z is found by...
« on: May 27, 2013, 09:53:28 pm »
0
A: reflecting z in the Im(z) axis
B: reflecting z in the Re(z) axis
C: reflecting z in the line Im(z) = Re(z)
D: rotating z through about the origin (i.e. anticlockwise)
D: rotating z through - about the origin (i.e. clockwise)

I'm fairly certain it is C:
i5 = i
therefore, u = xi - y

The thing is, I have to explain why all of the other options are correct. Heck, I have to explain why my option is correct. Because the x and y values have swapped....

Help appreciated
And I hope the text wraps work!
I am a mathhole

ahat

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 282
  • Monash MBBS class of 2018!
  • Respect: +9
  • School Grad Year: 2013
Re: Complex Numbers: u = i^5z is found by...
« Reply #1 on: May 27, 2013, 09:55:38 pm »
0
Lol, my bad

D: rotating z through π/2 about the origin (i.e. anticlockwise)
E: rotating z through -π/2 about the origin (i.e. clockwise)
I am a mathhole

brightsky

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3136
  • Respect: +200
Re: Complex Numbers: u = i^5z is found by...
« Reply #2 on: May 27, 2013, 11:14:11 pm »
0
the answer should be D. i^5*z = i*z.
2020 - 2021: Master of Public Health, The University of Sydney
2017 - 2020: Doctor of Medicine, The University of Melbourne
2014 - 2016: Bachelor of Biomedicine, The University of Melbourne
2013 ATAR: 99.95

Currently selling copies of the VCE Chinese Exam Revision Book and UMEP Maths Exam Revision Book, and accepting students for Maths Methods and Specialist Maths Tutoring in 2020!