CAS calculator - How do I find the asymptote on the graph page?

[NoticeMeSenpai]

Hello

I need a bit of help with my calculator. I know how to plot a graph, but I can't find the asymptote option in the "menu" section. Can anyone please help?

Thanks

[Daenerys Targaryen]

I don't think you can

[silverpixeli]

I haven't seen a way to find an asymptote. If there is one, let me know

[saba.ay]

Only with hyperbolas, I know that on the TI-nspire, you can find asymptotes, but with any other graph, I don't think such a function exists. :/

[Daenerys Targaryen]

How do you do the hyperbola one?

[b^3]

From memory it may have been under Analyze graph, but don't take that for 100% certain since I don't have the new calc on me atm.

Although for some graphs it's easier and quicker to do it by hand than to actually graph it....
For example if we have , then we can already tell that we will have asymptotes when and , as when , the denominator becomes zero, and the fraction goes off to infinity. While we can never have as the fraction can never be zero, but we can have approaching , as the fraction can approach .

In short for hyperbolas you should know how to find the asymptotes simply from reading off the graph. For others it can just take a little bit of manipulation. Although a small calc trick can be used if you want to check for vertical asymptotes. You can solve the curve to equal and solve for , which will be undefined, but this is what happens to our curve at asymptotes, as the curve goes off to infinity.

[saba.ay]

How do you do the hyperbola one?

For Ti-nspire, its:
Analyse Graph (6) => Analyse conics (8 ) => asymptotes (6).

[Cloud Nine]

I'm pretty sure you can't.

There was a question on my methods SAC a bit under two months ago in the application section that was essentially asking for the asymptote of y=10004/(1+e^(3-(x/2))).

The answer was 10004 and to this very day, I still have no idea how they got the answer lol.

I better go ask tomorrow.

[b^3]

So is an asymptote.

Also if you don't have the new option there you may need to update the OS on your calc.

[Cloud Nine]

So is an asymptote.

Also if you don't have the new option there you may need to update the OS on your calc.

Hmm wow, the question was only 1 mark though and I use the CAS calculator, version 03.06.1000, where can I go to check/obtain the latest OS?

Also, how did you get from x approaches infinite to 3 - (x/2) approaches negative infinite to e^(3-(x/2)) approaches 0?

I understand everything else though

[b^3]

Well if then what does approach? (Think about the line as you go all the way to the right to infinity or all the way to the left to negative inifinity).
Then if we are approaching negative infinity, and add a small number 3, we will still be approaching negative infinity.

Then for the exponential part, if we have , as then what will the curve of approach? (do a little sketch and look at the behavior of the curve as you go all the way to the left to negative infinity).

Regarding Update:

The CD should have software on it for the computer link. If not you can download it from here
http://education.ti.com/en/us/software/details/en/82035809F7E6474099944056CCB01C20/ti-nspire_computerlink
Then click through to download the update and then transfer and install to the calc.

EDIT: Added missing negative.

[Cloud Nine]

Well if then what does approach? (Think about the line as you go all the way to the right to infinity or all the way to the left to negative inifinity).
Then if we are approaching negative infinity, and add a small number 3, we will still be approaching negative infinity.

Then for the exponential part, if we have , as then what will the curve of approach? (do a little sketch and look at the behavior of the curve as you go all the way to the left to negative infinity).

Regarding Update:

Ahh wow, you're a really good explainer ahaha.
Thank you for that and I'm on my acerpad at the moment, so I'll check the link out when I can get on the computer.

Where was that quote from by the way?

Thanks again :-)

[b^3]

You can get the link by clicking on the 'quote from...' part normally (although may not work on acerpad or w.e.). Was from the Methods Resource Thread from a couple of days ago.
Re: Mathematical Methods CAS Resources

EDIT: Also it was meant to be u approaches negative infinity, not infinity. Fixed it now.