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November 01, 2025, 03:34:12 pm
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Author Topic: |z + 3| = |z -5i|  (Read 1033 times)  Share 

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tonychet2

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|z + 3| = |z -5i|
« on: June 06, 2013, 11:33:09 pm »
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how would one go about sketching this in the complex plain ? THANKS!

|z + 3| = |z -5i|
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thushan

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Re: |z + 3| = |z -5i|
« Reply #1 on: June 06, 2013, 11:34:43 pm »
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Quote from: tonychet2 on June 06, 2013, 11:33:09 pm
how would one go about sketching this in the complex plain ? THANKS!

|z + 3| = |z -5i|

Translating to english, find all points that are equidistant to (-3, 0) and (0, 5). You'll find you'll get a straight line perpendicular to the line between (-3, 0) and (0, 5).
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tonychet2

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Re: |z + 3| = |z -5i|
« Reply #2 on: June 06, 2013, 11:49:26 pm »
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thanks thushan!
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Conic

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Re: |z + 3| = |z -5i|
« Reply #3 on: June 07, 2013, 12:01:12 am »
+5
To convert complex equations to cartesian you let z=x+yi.







And keep going from there.

Also, when you have loci in that form the line is the perpendicular bisector to the line joining those 2 points, like Thushan said.
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