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November 08, 2025, 05:13:17 am
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Author Topic: Finding the domain from the INVERSE function?  (Read 858 times)  Share 

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captainoats

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Finding the domain from the INVERSE function?
« on: June 28, 2009, 05:26:53 pm »
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Hi there,

I have been given the following question:

The function f defined by f:A->R, where , will have an inverse function if its domain A is:

A. R
B. R+ U {0}
C. {x:x2}
D. {x:x3}
E. {x:x1}

I have gone as far as working out the equation of the inverse:

And I know that the range of the inverse is equal to the domain of the original, but how do I work this out?

Thanks!
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Flaming_Arrow

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Re: Finding the domain from the INVERSE function?
« Reply #1 on: June 28, 2009, 05:33:07 pm »
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for an inverse function to exist, the function must be a one to one function. after u sketch the graph you can see the turning point is at x = 3 therefore the answer is D
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captainoats

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Re: Finding the domain from the INVERSE function?
« Reply #2 on: June 28, 2009, 05:34:55 pm »
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Quote from: Flaming_Arrow on June 28, 2009, 05:33:07 pm
for an inverse function to exist, the function must be a one to one function. after u sketch the graph you can see the turning point is at x = 3 therefore the answer is D

Sweet, thanks so much!
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captainoats

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Re: Finding the domain from the INVERSE function?
« Reply #3 on: June 28, 2009, 05:39:32 pm »
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I would give you karma, but, i havent reached 50 posts yet  :-\
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