How would -4 < Re(z) < 4 look like?

[ahat]

The answer is C, I'm wondering how the other relations would look like?
(I initially thought it could be b)

[lzxnl]

A is basically a semicircle radius 16
B is still the entire circle as everywhere in the circle |z|<=4 satisfies -4<=Re(z)<=4
C is the right answer as you know
For D, z*z bar = (x+iy)(x-iy)=x^2+y^2, so D is the same as A
E is x^2+y^2<=4; the second restriction is correct, but it's a semcircle of radius 2.

[ahat]

B is still the entire circle as everywhere in the circle |z|<=4 satisfies -4<=Re(z)<=4

Oh my gosh, smack my head.

[abeybaby]

Can I ask, where did this question come from? It's not a vcaa paper is it?

[ahat]

Kilbaha 2006

[BubbleWrapMan]

I wonder if VCAA would care about the open circle at the origin which should be there if C is correct. I think they avoid questions with open circles...

[abeybaby]

I wonder if VCAA would care about the open circle at the origin which should be there if C is correct. I think they avoid questions with open circles...

Exactly why I asked!