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nhmn0301:
Hi, can you guys help me with this question:
Write a balanced ionic equation for the reaction between iodine and sodium thisulfate (Na2S2O3)
I2 (aq) + 2Na2S2O3 (aq) -> 2NaI (aq) + Na2S4O6 (aq)
Thanks for help!!

lzxnl:
In this reaction, the sodium ions don't really do anything so your ionic reaction is I2(aq)+2S2O32-(aq) => 2I-(aq) + S4O62-(aq)

Penguuu:
Hi guys, I would love some help with this question. Ive already got the worked out solutions but i still dont understand it.
25.00ml of a 0.100 M solution of HCl is added to 25.00ml of a 0.180 M solution of naOH.
The concentration of OH-(aq) remaining in the solution, in M is

A. 0.0400

Thanks!  :)

brightsky:
25.00mL of a 0.100 M solution of HCl is added to 25.00mL of a 0.180 M solution of NaOH. Find the concentration of OH-(aq) remaining in the solution in M.

The ionic equation for this reaction is:

H+(aq) + OH- (aq) --> H2O(l)

Note that Na+(aq) and Cl-(aq) are merely spectator ions.

n(H+) = n(HCl) = c*V = 0.02500*0.100 = 0.00250 mol
n(OH-) = n(NaOH) = c*V = 0.02500*0.180 = 0.00450 mol

It is clear that H+ is the limiting reagent. Hence, n(OH-) remaining after the reaction goes to completion is 0.00450 - 0.00250 = 0.00200.

This means that c(OH-) = n/V = 0.00200/0.05000 = 0.0400 M, as required.

eagles:
When a certain non-metal whose formula is X8 burns in air XO3 forms. Write a balanced equation for this reaction. If 120.0g of oxygen gas is consumed completely, along with 80.0g of X8, identify element X.

Is this balanced equation correct: X8 (g) + 12 O2 (g) -> 8XO3 (g)
I'm not sure how to proceed with this question....

Your help is appreciated   :D

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