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November 01, 2025, 03:35:02 pm

Author Topic: Complex number help?  (Read 1027 times)  Share 

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Yoda

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Complex number help?
« on: February 05, 2014, 06:34:37 pm »
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Need help with the following question

 Find the solutions to the equation z^4 -2z^2+4=0 in polar form.
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hobbitle

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Re: Complex number help?
« Reply #1 on: February 05, 2014, 06:59:53 pm »
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Hey mate,

I might not be doing this the most efficient way but this is how I'd do it (I won't type out all the steps because cfg using TeX, sorry)...

Let
-->
Solve using quadratic formula, you get:

Convert this to polar form using standard triangles to find the modulus and argument (modulus=2, argument=pi/3)

The result is the solution for z^2 so I guess you just take the sqrt of that to get your final answer.  I dunno i've been on holiday for like 3 months my brain is pretty dead.
« Last Edit: February 05, 2014, 07:15:45 pm by hobbitle »
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scribble

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Re: Complex number help?
« Reply #2 on: February 05, 2014, 09:46:03 pm »
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:)
(Sorry for the bad lighting)

hobbitle

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Re: Complex number help?
« Reply #3 on: February 05, 2014, 09:52:16 pm »
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^ what she did
2008 - 2010 | Bachelor of Production @ Victorian College of the Arts
2013 - 2015 | Bachelor of Science @ UoM (Bioengineering Systems)
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Yoda

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Re: Complex number help?
« Reply #4 on: February 06, 2014, 04:59:18 pm »
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Thanks very much, but can you please explain how you did the last line?
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Stevensmay

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Re: Complex number help?
« Reply #5 on: February 06, 2014, 07:00:15 pm »
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Last step is just an application of De Moivre's theorem which states that if

then


So in this question we have


And applying De Moivre's


Therefore



The other two solutions produced by square rooting are just those with complementary? angles.