Author Topic: wha?????? (Read 581 times) Tweet Share

wasssup · « **on:** April 25, 2014, 10:43:27 pm »

Please help
Q8b)

Conic · « **Reply #1 on:** April 25, 2014, 11:16:38 pm »

From 8a:

$\overrightarrow{AB}=\overrightarrow{OB}-\overrightarrow{OA}$

$=(3-t)\underset{\sim}{i}+(5-t)\underset{\sim}{j}$

Now for 8b we want to find when the length of this vector is at a minimum. The length of AB is given by:

$|\overrightarrow{AB}|=\sqrt{(3-t)^2+(5-t)^2}$

$=\sqrt{2t^2-16t+34}$

The minimum distance occurs when $2t^2-16t+34$ is at a minimum, i.e. when t=4.

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Author Topic: wha?????? (Read 581 times) Tweet Share

wasssup

wha??????

Conic

Re: wha??????

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