Just a question

[duhherro]

Hey guys just having trouble with this sort of question..
I have worked out a) but I don't know which limits to use in the integral for b) and c)

Thanks in advance!



An Australian Chamber Orchestra concert is to be broadcasted live on Classic FM. It is scheduled to begin at 7 pm sharp. Although every effort is made to ensure the concert will start on time (due to the live broadcast), it may still start anywhere between 6.55 pm and 7.05 pm. The difference (in minutes) between the advertised starting time and the actual starting time is a continuous random variable with probability density function given by

f(x) = (pi/20root2)  x  cos (xpi/20) , -5 <= x <= 5   (damn sorry about this disgusting formula that looks bad when typed out)

a What is the probability that the concert will start within 30 seconds of the scheduled time? Answer correct to 4 decimal places.
b Maya is listening to the concert at home. She turns on her radio at 6.58 pm. What is the probability that Maya will miss the beginning, correct to 4 decimal places?
c Patrons who arrive after the concert has started will not be admitted until the interval. Lena and Alex are caught in a traffic jam and estimate that they will arrive at the concert hall at 7.03 pm. Assuming that the couple will indeed arrive at their estimated time, what is the probability that they will be admitted, correct to 4 decimal places?

[BubbleWrapMan]

a)

b)

c)

[thumbsup]

Why is (a) from -0.5 to 0.5?

[Ledda]

Why is (a) from -0.5 to 0.5?

The x-axis is difference in minutes, and the question asks for 30 seconds either side of the scheduled time. 30 seconds = minute.

[thumbsup]

thank you : )