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October 21, 2025, 05:08:42 pm
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Author Topic: 2013 VCAA Question  (Read 678 times)  Share 

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rizzoo97

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2013 VCAA Question
« on: October 28, 2014, 04:33:56 pm »
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Hi!

Could anyone help me out with Question 7 of Graphs and Relations (2013 Exam 1), I'm having trouble with these sort of questions,

Thanks in advance :)
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2013/2013furmath1-w.pdf
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AbominableMowman

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Re: 2013 VCAA Question
« Reply #1 on: October 28, 2014, 05:18:04 pm »
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use the formula for finding the gradient
So you have 2 points on the graph and a graph with the rule H=m/d^2 with m being the gradient
m=y2-y1/x2-x1
your two points are 0.44,25.7 and 0,0
m=25.7-0/0.44-0
m=25.7/0.44
m=58.4, therefore the answer is A
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rizzoo97

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Re: 2013 VCAA Question
« Reply #2 on: October 28, 2014, 07:29:49 pm »
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Thanks a bunch!! :D
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