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November 01, 2025, 04:37:54 pm

Author Topic: Another circles intercepts question  (Read 999 times)  Share 

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JackSonSmith

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Another circles intercepts question
« on: December 25, 2014, 11:07:03 pm »
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Find the coordinates of the points of intersection of the curves

x^2 / 4  + y^2 / 9  = 1   and  x^2 / 9  +  y^2 / 4  = 1
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Tyleralp1

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Re: Another circles intercepts question
« Reply #1 on: December 25, 2014, 11:25:12 pm »
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Transpose each side for y:

y=sqrt(9-(9x^2)/4)
y=sqrt(4-(4x^2)/9)

Let the sides equal each other and square both sides:
9-(9x^2)/4 = 4-(4x^2)/9

Solve for x.

Sub answer back into equation, to find the respective y coordinate.


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Phy124

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Re: Another circles intercepts question
« Reply #2 on: December 25, 2014, 11:58:20 pm »
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Handy knowledge - If you have two ellipses of the form and , the points of interception of the two are given by .

How was this derived you might question? Simply put, one ellipse is the other flipped about the line (or similarly ) so we know they will intercept somewhere along these lines. Take one of the equations and sub in for , I'll use the first one. We have . We know the solutions are along the lines so the solutions for are the same and you now have your four points. Yay for killing time waiting to check out boxing day sales by doing maths ::)
« Last Edit: December 26, 2014, 12:24:33 am by Phy124 »
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Re: Another circles intercepts question
« Reply #3 on: December 26, 2014, 12:48:06 am »
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Yay for killing time waiting to check out boxing day sales by doing maths ::)

Then doing more maths because they didn't calculate the new price for you, they just told you the discount. ;)

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Re: Another circles intercepts question
« Reply #4 on: December 26, 2014, 12:54:41 am »
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Transpose each side for y:

y=sqrt(9-(9x^2)/4)
y=sqrt(4-(4x^2)/9)

Let the sides equal each other and square both sides:
9-(9x^2)/4 = 4-(4x^2)/9

Solve for x.

Sub answer back into equation, to find the respective y coordinate.

I'd solve for y^2 instead and set them equal to each other.
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