Login

Welcome, Guest. Please login or register.

November 01, 2025, 12:44:15 pm

Author Topic: need some help on this  (Read 1388 times)  Share 

0 Members and 1 Guest are viewing this topic.

JuzzLee

  • Victorian
  • Trailblazer
  • *
  • Posts: 32
  • Respect: +2
need some help on this
« on: August 10, 2009, 01:21:19 pm »
0
hey, i got a question here, any idea? thanks

100ml of a 0.1 M HS- solution and 100 ml of a 0.2 M HSO3- solution are added separately to two conical flasks containing 100 ml of water. which of the following could be used to accurately determine which acid is the stronger species?

(a) Conductivity
(b) pH
(c) concentration
(d) Equilibarium constant

another question:

The pH of a 10^-9 M solution of HCl is closest to:
(a) 4
(b) 6
(c) 7
(d) 9

i got 9 which is incorrect
« Last Edit: August 10, 2009, 03:00:19 pm by JuzzLee »
IT @ RMIT

lukeperry91

  • Victorian
  • Trendsetter
  • **
  • Posts: 183
  • Respect: +1
Re: need some help on this
« Reply #1 on: August 10, 2009, 03:43:30 pm »
0
hey, i got a question here, any idea? thanks

100ml of a 0.1 M HS- solution and 100 ml of a 0.2 M HSO3- solution are added separately to two conical flasks containing 100 ml of water. which of the following could be used to accurately determine which acid is the stronger species?

(a) Conductivity
(b) pH
(c) concentration
(d) Equilibarium constant



A) In many cases, conductivity is linked directly to the total dissolved solids (T.D.S.), therefore it is not A as the total ammount of solids (atoms) doesn't change.
B) This is a measure of an acids concentration, which is irrespective to its strength
C) "
D) By cancellation this is correct. Also, the strength of an acid determines how readily it will dissociate in water (donate H+ atoms) and the stronger an acid is, the more it will donate, therefore the larger the product:reactant ratio (:. higher K). Therefore the strength of an acid or base correlates to its Ek value.


The pH of a 10^-9 M solution of HCl is closest to:
(a) 4
(b) 6
(c) 7
(d) 9

i got 9 which is incorrect

[H3O+]=[HCl] as Hydrochloric acid is a strong acid and will completely dissociate.
pH=-log10[H3O+]
:. pH=-log10[10-9]
:. pH is 9

No idea how its nine, I'd imagine it would have to be below 7, but only slightly, so I'm gonna say C because of the tiny concentration.
Year 12 2009
Biology
Chemistry
Methods CAS
Physics
English

Ambitions
Biomed at melbourne
Travel
Have a nice family
[img]http://dl.getdropbox.com/u/530203/merspi_small.png[/img]

lukeperry91

  • Victorian
  • Trendsetter
  • **
  • Posts: 183
  • Respect: +1
Re: need some help on this
« Reply #2 on: August 10, 2009, 03:57:03 pm »
0
For question two, pH Calculator
         

[quote pH Calculation Results


The contribution of water to the pH has been accounted for due to the low concentration of hydrochloric acid.


The pH of .00000001 M hydrochloric acid is 6.98.

The chemical formula for hydrochloric acid is HCl.

The molecular weight for hydrochloric acid is 36.46097 grams/mole. "
[/quote]
Basically, the effect of the additional formation of hydronium ions causes no significant change to the pH of the solution, I think I remember reading something about this in Heinemann 1. A link to the website I used: http://www.sensorex.com/support/education/pH_calculator.html

The 'flag' word in this question is "...is closest to..." this generally means that the exact answer isn't calculable and you need to refer to knowledge other than the pH formula.
Year 12 2009
Biology
Chemistry
Methods CAS
Physics
English

Ambitions
Biomed at melbourne
Travel
Have a nice family
[img]http://dl.getdropbox.com/u/530203/merspi_small.png[/img]

JuzzLee

  • Victorian
  • Trailblazer
  • *
  • Posts: 32
  • Respect: +2
Re: need some help on this
« Reply #3 on: August 10, 2009, 10:59:57 pm »
0
oh i see, thanks man. your getting 50
IT @ RMIT

ryley

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 239
  • Respect: +2
Re: need some help on this
« Reply #4 on: August 10, 2009, 11:21:45 pm »
0
I think you can do this by hand/calc, to work out the pH, you have to take the negative log of the concentration of H+ in neutral water (10^-7) AND the concentration of H+ from the acid (10^-9), so your final expression for pH should be pH=-log(10^-7+10^-9), which comes out to be 6.99. Its been a while since I did this question, so either I remembered the basis of the procedure, or its a very useful coincidence.
2008: 3/4: Biology[41]
2009: 3/4: English[37], Chemistry[43], Methods(CAS)[46], Physics[39], Specialist[46]
ENTER: 98.85
B.Sc(Applied Maths) @ Melbourne Uni

Mao

  • CH41RMN
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 9181
  • Respect: +390
  • School: Kambrya College
  • School Grad Year: 2008
Re: need some help on this
« Reply #5 on: August 11, 2009, 10:57:56 pm »
0
I think you can do this by hand/calc, to work out the pH, you have to take the negative log of the concentration of H+ in neutral water (10^-7) AND the concentration of H+ from the acid (10^-9), so your final expression for pH should be pH=-log(10^-7+10^-9), which comes out to be 6.99. Its been a while since I did this question, so either I remembered the basis of the procedure, or its a very useful coincidence.

That is correct. When adding a very very diluted acid (or base), the products of self-ionisation of water can make a significant contribution. In this case, the addition of a 10^-9 M acid is very insignificant compared to the neutal H+ concentration of 10^-7, hence pH will still be around 7.

The only reason we usually ignore the products of self-ionisation is because the usual concentration of acids we deal with are of a much higher magnitude than 10^-7
Editor for ATARNotes Chemistry study guides.

VCE 2008 | Monash BSc (Chem., Appl. Math.) 2009-2011 | UoM BScHon (Chem.) 2012 | UoM PhD (Chem.) 2013-2015

JuzzLee

  • Victorian
  • Trailblazer
  • *
  • Posts: 32
  • Respect: +2
Re: need some help on this
« Reply #6 on: August 12, 2009, 09:18:55 pm »
0
thanks guys
IT @ RMIT