HSC Stuff > HSC Mathematics Extension 2

Can VCE'ers compete with HSC Maths?

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pi:

--- Quote from: Conic on June 27, 2015, 09:02:17 pm ---What did you do here?

--- End quote ---

Looked a bit fluffy :P

Probably should have used arg(ab) = arg(a) + arg(b), hence arg((1+i)((1+2i)(1+3i)) = arg(-10) = pi

cosine:

--- Quote from: pi on June 27, 2015, 09:07:49 pm ---Looked a bit fluffy :P

Probably should have used arg(ab) = arg(a) + arg(b), hence arg((1+i)((1+2i)(1+3i)) = arg(-10) = pi

--- End quote ---

I simply just added the arguments together, why do you multiply them may I ask? :)

keltingmeith:

--- Quote from: cosine on June 27, 2015, 09:23:14 pm ---I simply just added the arguments together

--- End quote ---

You did - you didn't actually show that they were pi, though. You showed that computationally, they would approximate pi, but not that they were exactly pi.

By doing as pi has done, you show that they are exactly pi.

pi:

--- Quote from: EulerFan101 on June 27, 2015, 09:28:09 pm ---By doing as pi has done, you show that they are exactly pi.

--- End quote ---

I had to read this 5 times LOL

keltingmeith:

--- Quote from: pi on June 27, 2015, 09:29:55 pm ---I had to read this 5 times LOL

--- End quote ---

#metaaf

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