Login

Welcome, Guest. Please login or register.

November 01, 2025, 07:38:24 pm

Author Topic: Alternate Segment Theorem  (Read 3173 times)  Share 

0 Members and 1 Guest are viewing this topic.

archiebear

  • Guest
Alternate Segment Theorem
« on: January 17, 2016, 01:23:15 am »
0
"The angle between a tangent and a chord drawn from the point of contact is equal to any angle in the alternate segment"
Can someone please elaborate on this, what does it mean by "in the alternate segment"?

I don't understand how these angles are alternate to each other
Some help please?

Syndicate

  • Forum Leader
  • ****
  • Posts: 797
  • Hard work beats Talent
  • Respect: +139
Re: Alternate Segment Theorem
« Reply #1 on: January 17, 2016, 11:07:20 am »
+1
"The angle between a tangent and a chord drawn from the point of contact is equal to any angle in the alternate segment"
Can someone please elaborate on this, what does it mean by "in the alternate segment"?
(Image removed from quote.)
I don't understand how these angles are alternate to each other
Some help please?

Hey,

So a segement is the area, outside the triangle, but inside the circle. What your question means to say is that all the segments (there are 3 segemtns here) has the same angle, thus you have an equalaterial triangle. You will need a bit of knowledge of angles made in parallel lines, which are cut off by a transveral line. There is a lot of information loaded here about that: http://www.mathwarehouse.com/geometry/angle/parallel-lines-cut-transversal.php
2017: Chemistry | Physics | English | Specialist Mathematics | Mathematics Methods
2018-2020 : Bachelor of Biomedicine at University of Melbourne

Physics Guide 2017

archiebear

  • Guest
Re: Alternate Segment Theorem
« Reply #2 on: January 18, 2016, 02:34:49 pm »
0
Hey,

So a segement is the area, outside the triangle, but inside the circle. What your question means to say is that all the segments (there are 3 segemtns here) has the same angle, thus you have an equalaterial triangle. You will need a bit of knowledge of angles made in parallel lines, which are cut off by a transveral line. There is a lot of information loaded here about that: http://www.mathwarehouse.com/geometry/angle/parallel-lines-cut-transversal.php

uhh, it's not necessarily an equilateral triangle, if theta was say for example, 40 degrees, it would not be an equilateral triangle.
Also, there are no parallel lines shown in this diagram, what i'm really asking for is how theta in this case is alternate to the other theta and why are they equal.
Thanks

wyzard

  • Forum Obsessive
  • ***
  • Posts: 237
  • Respect: +42
Re: Alternate Segment Theorem
« Reply #3 on: February 04, 2016, 11:12:48 am »
0
"The angle between a tangent and a chord drawn from the point of contact is equal to any angle in the alternate segment"
Can someone please elaborate on this, what does it mean by "in the alternate segment"?
(Image removed from quote.)
I don't understand how these angles are alternate to each other
Some help please?
The "alternate" in the alternate segment theorem refers to the segment on the other side of segment containing the tangent's angle. Notice how the angle is sandwiched between the 2 segments on other side. It's just a conventional theorem name in maths, you can call it "Other side angle theorem" if that makes it easier for you to visualize 8)
Graduated from high school in 2012 with atar of 99.55.

Currently doing MSc in Physics at UoM researching on Quantum Computers.

Offering group lessons for Unit 3/4 VCE Methods and Physics for 2017!

Selling awesome and in-depth study notes for Unit 3 Physics, PM me if interested! :D

Writer/Tutor at (Nerd of Passion)!
Connect with me on Facebook!