Stoich

[mandy]

100mL of 1.00M KOH is mixed with 32.5mL of 2.00M H₃PO₄, and allowed to react according to the equation:

3KOH (aq) +  H₃PO₄ (aq) -----> K₃PO₄ (aq) + 3H₂O (l)

a. calculate the amount in moles of each reactant and determine the limiting reagent.
Doesn't n(KOH) = cV
                     = 1.00 * 0.1 = 0.1 mol ?
The answer says its 0.010 mol. How ? Is this a typo ?

b. what is the mass of the K₃PO₄ formed?

[d0minicz]

i would think