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November 01, 2025, 11:20:10 am

Author Topic: Equilibrium Constant Question  (Read 1123 times)  Share 

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eforlano

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Equilibrium Constant Question
« on: July 17, 2016, 03:28:47 pm »
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I'm a bit confused on this question :/

Upon dissolving in water, the sugar alpha-d-glucose undergoes conversion into an isomer called beta-d-glucose. This process is called mutarotation and reaches equilibrium when 63.6% of the original alpha-d-glucose has been converted. Calculate the value of the equilibrium constant for this process.

The answer says the value is 1.74... ahhh help please :)

Sine

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Re: Equilibrium Constant Question
« Reply #1 on: July 17, 2016, 03:38:06 pm »
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I'm a bit confused on this question :/

Upon dissolving in water, the sugar alpha-d-glucose undergoes conversion into an isomer called beta-d-glucose. This process is called mutarotation and reaches equilibrium when 63.6% of the original alpha-d-glucose has been converted. Calculate the value of the equilibrium constant for this process.

The answer says the value is 1.74... ahhh help please :)
I'm just gonna call them alpha and beta for simplicity.

So Initially there is 100% alpha and 0% beta. Then isomerisation occurs converting alpha to beta.

At the end there is unknown alpha (for now) and 63.6% beta, since isomerisation is a 1 to 1 ratio we can say that the amount of beta produced was the same as alpha lost. i.e Change in concentration to alpha was 100-x and increase in beta concentration was 0+x  = 63.6
Therefore x = 63.6%
So then we can say alpha concentration is 100-63.6 = 36.4%

k=[beta]/[alpha] = (63.6)/(36.4) = 1.75

We could have also summarised this all in an ICE table
I(initial), C(change), E(equilibrium)
   alpha     beta
I  100         0
C -x           +x
E  100-x      63.6
Solved for x then calculated K