HSC Stuff > HSC Information Processes and Technology

IPT Question Thread + Useful Info

<< < (7/13) > >>

aimbotted:

--- Quote from: Hua Fei on October 09, 2016, 11:57:44 pm ---Have a go at these two     :)

--- End quote ---

B and C!

BPunjabi:

--- Quote from: Hua Fei on October 09, 2016, 11:57:44 pm ---Have a go at these two     :)

--- End quote ---

Not the slightest clue for the second question

Hua Fei:

--- Quote from: BPunjabi on October 10, 2016, 12:01:57 am ---Im guessing a) for 1, I dont know its odd and a 1, all the rest are even

--- End quote ---

10) Even number of ones in the given scenario therefore even parity has been used. For errors to be detected, one of the options will give an odd number of ones. Hence, the answer is b) (not a) since even parity is used and error would not be detected)

19) Odd parity has been selected hence, for error to be detected, we're looking for even parity in one of the options. Therefore the answer is c)  (don't know what answer you suggested)

Hua Fei:

--- Quote from: BPunjabi on October 10, 2016, 12:01:57 am ---Im guessing a) for 1, I dont know its odd and a 1, all the rest are even

--- End quote ---

Also, for question 10, a) has 6 number of 1's hence its even but b) would be odd since there are 5 number of 1's

BPunjabi:
Guys I sorta get it but not completely now... is there a slow and basic way you can explain to me because I know every other element of IPT except for this and its pis*ing me off

Navigation

[0] Message Index

[#] Next page

[*] Previous page

Go to full version